- #1
coverband
- 171
- 1
speed = distance/time
v=s/t
Acceleration = dv/dt = -s/t^2 ?
v=s/t
Acceleration = dv/dt = -s/t^2 ?
DrGreg said:Another thing to add is that the differentiation in post #1 would be valid only if ##s## were a constant and ##t## were a variable. Does that make sense?
I said constant ##s##, not constant ##a##. My comments refer specifically to $$coverband said:No because when deriving an equation for v we start with a = dv/dt -> dv = a dt -> v=[int]a dt -> v = u + at. This is how Wikipedia derives the first equation of motion. They treat a as a constant. Thanks for your first answer though
Velocity is a vector quantity that describes the rate of change of an object's position over time, including its direction. Acceleration, on the other hand, is a vector quantity that describes the rate of change of an object's velocity over time.
Acceleration is the derivative of velocity, meaning it is the rate of change of velocity over time. In other words, if an object's velocity changes, it will experience acceleration.
Velocity is typically measured in meters per second (m/s) or kilometers per hour (km/h), while acceleration is measured in meters per second squared (m/s²) or kilometers per hour squared (km/h²).
Velocity can be calculated by dividing the change in an object's position by the change in time. Acceleration can be calculated by dividing the change in an object's velocity by the change in time.
Yes, an object can have a constant velocity and still experience acceleration if its direction changes. This is because acceleration takes into account the change in both speed and direction.