Understanding Velocity and Vector Calculus for Moving Objects

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SUMMARY

The discussion focuses on the motion of an object defined by the position vector r(t) = (1+t^2)i + (1-t)j + (t+t^3)k. At t=1, the object's velocity is calculated as r'(1) = 2i - j + 4k. The participants explore the relationship between the position vector and the velocity vector, questioning whether the derivative r'(t) represents the object's velocity accurately. The confusion arises regarding the interpretation of velocity in relation to the position vector.

PREREQUISITES
  • Understanding of vector calculus
  • Familiarity with derivatives and their physical interpretation
  • Knowledge of parametric equations in three-dimensional space
  • Basic concepts of motion in physics
NEXT STEPS
  • Study the concept of velocity vectors in vector calculus
  • Learn about the relationship between position and velocity in motion analysis
  • Explore the application of derivatives in physics, particularly in kinematics
  • Investigate the implications of higher-order derivatives in motion
USEFUL FOR

Students studying physics or mathematics, particularly those focusing on vector calculus and motion analysis, as well as educators seeking to clarify concepts related to velocity and position vectors.

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Homework Statement



An object moves according to this : r(t)= (1+t^2)i + (1-t)j + (t+t^3)k

How fast does it moves far from O(0,0) for t=1?

Is this velocity the same with the object's velocity?


The Attempt at a Solution



I can't understand the second part
 
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I can't seem to understand the second part either.

By the first one, do you mean, what its velocity is at t = 1, or what its position is? What is the relation between the two?
 
i mean the velocity for t=1 which is r'(1)= 2i-j+4k
The r(t) in my previous post is the position vector from the start (0,0)

is the any reason for not the r'(t) or r'(1) to be the objects velocity?
 

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