Understanding Virtual Images in Lenses and Mirrors

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SUMMARY

The discussion centers on the formation of virtual images using a converging lens with a focal length of 32 cm, specifically when viewing an object (a stamp) located 17 cm in front of the lens. The lens formula, 1/f = 1/do + 1/di, is applied, resulting in a calculated image distance (di) of -32.267 cm, confirming that the image is virtual. The negative value indicates that the virtual image is formed on the same side as the object, which can lead to confusion regarding the terminology of "front" and "behind" in lens optics.

PREREQUISITES
  • Understanding of lens formulas, specifically 1/f = 1/do + 1/di
  • Knowledge of converging lenses and their properties
  • Familiarity with the concept of real and virtual images
  • Basic grasp of optical terminology related to lenses
NEXT STEPS
  • Study the principles of lens optics, focusing on converging and diverging lenses
  • Learn about ray diagrams for both real and virtual images
  • Explore the differences between real and virtual images in various optical systems
  • Investigate the impact of lens curvature on image formation
USEFUL FOR

Students of physics, optical engineers, and anyone interested in understanding the behavior of light through lenses and the formation of images.

whitehorsey
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1. A stamp collector uses a converging lens with focal length 32 cm to view a stamp 17 cm in front of the lens.

Where is the image located?
a. in front of the lens (real image)
b. behind the lens (virtual image)


2. 1/f = 1/do + 1/di


3. 1/32 = 1/17 + 1/di
di = -32.267 cm

Because it's negative it is a virtual image.

For this problem, I imagined

front behind
---f--do---lens-----------

A virtual image is in the same side as the object. So something like this:
http://www.pa.msu.edu/courses/2000fall/PHY232/lectures/lenses/virtual_image.gif


So then why does the answer say if its virtual it is behind the lens? Also, what is considered front/behind for lens/mirrors?
 
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I think it is referring to the viewer. Behind the lens for the viewer is in front for the lens.
 
Thank You!
 
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