Understanding When to Use + / - in Pythagorean Identity

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The discussion focuses on understanding when to use positive or negative signs in the context of the Pythagorean identity, specifically for secant values. It emphasizes that the sign of a trigonometric function depends on the angle's quadrant; for instance, sec θ is negative in Quadrants II and III. The original question arises from confusion about the sign of sec θ when given a specific value, highlighting that without knowing the angle's location, one cannot determine the correct sign. The example provided illustrates that if tan θ is positive and sin θ is negative, the angle must be in the third quadrant, thus requiring a negative secant value. Understanding the relationship between the angle's quadrant and the signs of trigonometric functions is crucial for accurate calculations.
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Homework Statement



How would I know if let's say

Sec^2 = 5 / 4
Sec = +/- \sqrt{5/4}
Sec = + / - \sqrt{5} / 2

Now how would I know if whether to put a negative sign or a positive sign before the answer?

Because the textbook says Sec Theta < 0 therefor they added the negative sign, only.
What does this mean?

How is Sec < 0 if it equals \sqrt{5} / 2 ? This is not less than 0 so shouldn't we use a positive symbol?

Thanks



Homework Equations





The Attempt at a Solution

 
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First off, please don't write a trig function without the angle. It's sec θ, not sec.

A trig ratio is positive or negative depending on the angle. Was there any mention of the angle itself, or the location of the point on the terminal side? sec θ = r/x, and if sec θ < 0 then x must be negative. Must be an angle in Quadrant II or III, then.

The title of your thread is "Pythagorean Identity," so I'm guessing you're making use of
1 + tan2θ = sec2θ. Were you told anything about tan2θ? It would have been helpful if you posted the entire problem and not just a piece of it.
 
I apologize.

"Given that tan θ = 1/2 and sin θ <0, find the exact value of each of the remaining five trigonometric functions of θ."

yes, they used;
1 + (tan^2) θ = (sec^2) θ
 
as tan is +ve and sin is -ve,the angle lies in the 3rd quadrant where sec is negtive,so u shld take the -ve value
 

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