Understanding When to Use + / - in Pythagorean Identity

  • Thread starter Thread starter CrossFit415
  • Start date Start date
  • Tags Tags
    Identity
Click For Summary

Homework Help Overview

The discussion revolves around understanding the application of the Pythagorean identity in trigonometry, specifically regarding the secant function and the conditions under which it can be positive or negative based on the angle's quadrant.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the reasoning behind the sign of the secant function given a specific value and the conditions set by the textbook. Some participants question the importance of the angle's quadrant in determining the sign of the secant function.

Discussion Status

Participants are exploring the relationship between the angle's quadrant and the sign of the secant function. Some guidance has been offered regarding the implications of the angle's location, but there is no explicit consensus on the interpretation of the original problem.

Contextual Notes

There is a mention of specific conditions for the angle, such as tan θ being positive and sin θ being negative, which suggests a particular quadrant for the angle. However, the complete problem statement is not fully provided, leaving some assumptions unverified.

CrossFit415
Messages
160
Reaction score
0

Homework Statement



How would I know if let's say

Sec^2 = 5 / 4
Sec = +/- [tex]\sqrt{5/4}[/tex]
Sec = + / - [tex]\sqrt{5}[/tex] / 2

Now how would I know if whether to put a negative sign or a positive sign before the answer?

Because the textbook says Sec Theta < 0 therefor they added the negative sign, only.
What does this mean?

How is Sec < 0 if it equals [tex]\sqrt{5}[/tex] / 2 ? This is not less than 0 so shouldn't we use a positive symbol?

Thanks



Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
First off, please don't write a trig function without the angle. It's sec θ, not sec.

A trig ratio is positive or negative depending on the angle. Was there any mention of the angle itself, or the location of the point on the terminal side? sec θ = r/x, and if sec θ < 0 then x must be negative. Must be an angle in Quadrant II or III, then.

The title of your thread is "Pythagorean Identity," so I'm guessing you're making use of
1 + tan2θ = sec2θ. Were you told anything about tan2θ? It would have been helpful if you posted the entire problem and not just a piece of it.
 
I apologize.

"Given that tan θ = 1/2 and sin θ <0, find the exact value of each of the remaining five trigonometric functions of θ."

yes, they used;
1 + (tan^2) θ = (sec^2) θ
 
as tan is +ve and sin is -ve,the angle lies in the 3rd quadrant where sec is negtive,so u shld take the -ve value
 

Similar threads

Replies
10
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
5
Views
2K
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K