Understanding XRay Emission: Maximum Frequency and Derivation Explained

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SUMMARY

The discussion centers on the emission of X-ray photons resulting from electrons accelerated through a potential difference of 70,000 volts between a cathode and an anode. The maximum frequency of the emitted X-ray wave can be derived using the equation E = hf, where E represents the energy of the electron, h is Planck's constant, and f is the frequency. The energy of the electron in this scenario is calculated to be 70,000 eV, leading to a maximum frequency of approximately 1.68 x 1019 Hz for the emitted X-ray.

PREREQUISITES
  • Understanding of basic electron physics
  • Familiarity with X-ray generation principles
  • Knowledge of Planck's constant and its application
  • Basic grasp of energy-frequency relationships in electromagnetic radiation
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  • Research the derivation of the energy-frequency relationship using E = hf
  • Explore the principles of X-ray production in medical imaging
  • Study the effects of varying electric potentials on X-ray emission
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Physicists, medical imaging technicians, and students studying electromagnetism and radiation physics will benefit from this discussion.

xieon
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Sorry if this is the wrong forum.

There is a cathode and an anode and one is emmiting an electron (whichever one of the two does that, I honestly forget)

The electron moves through a electric potentinal of 70,000 volts. When it reaches the other side an Xray photon is emitted.

1) What is the maximum frequency of the XRay wave.

and how is that derived
 
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I won't be giving you any more hints as you have not shown any effort nor have you stated what you know.

Find the energy of the electron.
 
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