Undetermined Coefficients Method for Solving ODEs

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SUMMARY

The discussion focuses on solving the ordinary differential equation (ODE) x' = -x + ce^{-\beta t} using the Undetermined Coefficients Method. The particular solution is identified as x_p = \alpha e^{-\beta t}, with the coefficient α determined to be α = \frac{c}{-\beta + 1}. Participants emphasize the importance of finding the complementary solution to the homogeneous equation x' = -x and combining it with the particular solution to form the general solution.

PREREQUISITES
  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with the Undetermined Coefficients Method
  • Knowledge of complementary and particular solutions
  • Basic calculus concepts, including derivatives and exponential functions
NEXT STEPS
  • Study the method of Undetermined Coefficients in greater detail
  • Learn how to find complementary solutions for first-order linear ODEs
  • Explore examples of solving non-homogeneous ODEs
  • Investigate the application of Laplace transforms for solving ODEs
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Students and educators in mathematics, particularly those studying differential equations, as well as anyone seeking to enhance their problem-solving skills in ODEs using the Undetermined Coefficients Method.

Unassuming
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Homework Statement



(I am using b, for beta)

Let

[tex]f(t)=ce^{-\beta t}[/tex]

with b a fixed number and c in R is arbitrary but given.

Write the general solution of

[tex]x'=-x+f(t)=-x+ce^{-\beta t}[/tex]

Hint: Use undetermined coeff. and consider a particular solution of the form

[tex]x_p=\alpha e^{-\beta t}[/tex]

and determine [tex]\alpha[/tex]

Homework Equations





The Attempt at a Solution



I have solved for

[tex]\alpha = \frac{c}{-\beta +1}[/tex]
 
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Unassuming said:
Write the general solution of

[tex]x'=-x+f(t)=-x+ce^{-\beta t}[/tex]

I have solved for

[tex]\alpha = \frac{c}{-\beta +1}[/tex]

Hi Unassuming! :smile:

(have an alpha: α and a beta: β :smile:)

What's the difficulty?

You have found a particular solution, (c/(1-β))e-βt.

Now just find the complementary solution, ie the solution to x' = -x, and add it. :smile:
 

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