Unifom accelaration question about racing

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Homework Help Overview

The problem involves two go-carts racing around a 1.0 km track, with one cart traveling at a constant speed and the other accelerating uniformly from rest. The original poster seeks to determine which go-cart wins the race and by what margin.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of the track's shape, with some questioning whether it is circular or straight. The original poster mentions a constant speed for one cart and uniform acceleration for the other, but expresses uncertainty about which equations to use for calculations.

Discussion Status

Some participants have provided equations and suggested methods for calculating the time taken by each go-cart to complete the race. There is an acknowledgment of confusion among the original poster and others regarding the application of these equations, but guidance has been offered to clarify the approach.

Contextual Notes

The original poster notes that the physics teacher has been away, contributing to the class's confusion about the topic. There is a request for assistance without a clear resolution yet.

captdestiny
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Homework Statement


Two go-carts, A and B, race each other around a 1.0km track. Go cart A travels at a constant speed at 20.0m/s . Go cart B accelerates uniformly from rest at a rate of 0.333m/s2. Which go-cart wins the race ? and by how much ?

EDIT: When it says around it means they raced one lap around the track going at a constant speed, except for Cart B, its going at a constant acceleration

Don't go too deep into the shape of the track, it doesn't really matter, however if you still do, its going in a straight path.

Homework Equations


I don't know which to use.

The Attempt at a Solution



Well I know that Go-Cart A take 50 seconds to cross the line.

20m/s / 1000m = 50 seconds
 
Last edited:
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Do you mean to say that the track is not circular? After all, you said that
race each other around
, by "around", did you mean perhaps that the segment is round?
If not, recall that kinematics equations:
[itex] \large<br /> x = \frac{at^2}{2}[/itex]
Where a is your constant acceleration; But do clarify your stance on the shape of field etc...
Daniel
 
Fixed
 
Okay, thank's for allaying the mix-up.
What's stopping you from using the equation above? Find the time it took each to cross said distance, which will indicate firstly, who won... Then, measure how deficient/far was the loser by that moment in time.
Daniel
 
Don't know what equation to use ...

so lost.. physics teacher was away for a week and the whole class is lost
 
Okay, okay, not to worry, there's no need to panic.
You have, from my post:
[itex] \large<br /> x = \frac{at^2}{2}[/itex]
So plug in your data here for each car.
In one, x is simply v*t(the one with the constant velocity).
in the other, the above mentioned formula.
Find T for each(a is the constant acceleration).
Compare the results; Whosever t is greater, lost the race(took him longer to cross the track).
Then, find where was the loser at the time T of the victor.
It's as simple as that,
But it would help greatly if you could point-out where you're having difficulties,
Daniel
 
Thanks a lot Daniel, you're a life saver

MAY GOD BLESS YOUR WARM KIND HEART ! <33333333333333333
 
So I reckon you solved it properly, well done! :)
Good job,
And keep up the good work,
Daniel
 

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