EMF induced in rotating rod inside uniform magnetic field

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Homework Help Overview

The discussion revolves around a problem involving electromagnetic induction, specifically focusing on a rotating rod within a uniform magnetic field. The scenario includes a 40 cm rod rotating at a speed of 15 rad/s in a magnetic field of 6.4 T, with the goal of determining the potential difference between the center and the ends of the rod.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the formula for emf and the area covered by the rod during rotation. There are questions about whether to use the full period or half period for calculations, and the implications of using the diameter versus the radius in the area formula.

Discussion Status

Some participants have provided guidance on the correct approach to calculating the emf, emphasizing the need to consider the area covered by the half rod during one full period. There is also a discussion about the potential emf between the two ends of the rod, with some suggesting it would be zero.

Contextual Notes

Participants are navigating the specifics of the problem setup, including the definitions of radius and diameter, as well as the implications of the area used in the calculations. There is an ongoing exploration of the assumptions regarding the emf between different points on the rod.

songoku
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Homework Statement


A 40 cm rod is rotated about its centre inside a region of uniform magnetic field of 6.4 T. Given that the speed of rotation is 15 rad/s, find potential difference between the centre and either end of the rod

Homework Equations


emf = - ΔΦ / Δt

ω = 2π / T

The Attempt at a Solution


emf = - B cos θ . ΔA / Δt = - B . πr2 / T

I just need to plug the numbers with r = 20 cm (because from center to either end of rod)?

Thanks
 
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In one full period T, the radius of the rod which is ##r=20cm## (since ##d=40cm## is the diameter) covers a surface of a full circle which is ##\pi r^2##. You can use the diameter but then you ll have to take the formula ##\pi\frac{d^2}{4}## for the surface of the circle.
 
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Delta2 said:
In one full period T, the radius of the rod which is ##r=20cm## (since ##d=40cm## is the diameter) covers a surface of a full circle which is ##\pi r^2##. You can use the diameter but then you ll have to take the formula ##\pi\frac{d^2}{4}## for the surface of the circle.

For the time, do I use the period because half of the rod travels full circle in one full period or I use half of period because one whole rod covers one full circle in half period?

Thanks
 
songoku said:
For the time, do I use the period because half of the rod travels full circle in one full period or I use half of period because one whole rod covers one full circle in half period?

Thanks
You use the full period for half rod, otherwise if you follow the 2nd approach you find the EMF between the two ends of the rod. But the problem asks for the EMF between one end and the center, that's why we have to take the area that the half rod covers in one full period.
 
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Delta2 said:
You use the full period for half rod, otherwise if you follow the 2nd approach you find the EMF between the two ends of the rod. But the problem asks for the EMF between one end and the center, that's why we have to take the area that the half rod covers in one full period.

If the question asks the emf between two ends of the rod, will the answer be zero because they have the same value and the difference = 0?

Thanks
 
songoku said:
If the question asks the emf between two ends of the rod, will the answer be zero because they have the same value and the difference = 0?

Thanks
Yes, the emf between the two ends is zero.
 
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Thank you very much
 
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