Uniform centripetal acceleration

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SUMMARY

The discussion focuses on calculating the centripetal acceleration and tension in a system where a 3.0 kg ball revolves uniformly in a circle with a radius of 1.40 m at a frequency of 2 revolutions per second. The centripetal acceleration is derived using the formula ac = v²/r, while the tension in the string is equated to the centripetal force. The tension is calculated to be 0.5 N based on the provided frequency and radius.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula (ac = v²/r)
  • Knowledge of circular motion and tension in strings
  • Familiarity with the concept of frequency in revolutions per second
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate centripetal acceleration for varying masses and radii
  • Explore the relationship between frequency and angular velocity
  • Learn about forces in circular motion and their applications
  • Investigate the effects of friction on centripetal motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to centripetal acceleration and tension in strings.

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Homework Statement


A small ball with a mass of 3.0kg revolves uniformly in a circle on a frictionless horizontal surface. The ball is attached to a string of 1.40m to a pin set at center of circle. The object makes 2rev/sec.

a)find the centripetal accel
b)find the tension exerted on the string

Homework Equations



ac=v^2/r
Fc= ma=m(4pi^2r/T^2)
T= .5


The Attempt at a Solution


if its uniform wouldn't the Fc=FT(force of tension)
T would =.5 because 2 rev/1 sec?
I am not sure how to find centripetal accel because i do not know how to find the velocity unless i am missing something..
 
Last edited:
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If it makes one revolution and the string is 1.40 m, how much distance does it cover?
 

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