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## Homework Statement

for the differential equation

t^2y''-2ty'+2y=0 with the general solutions y=C(t) + D(t^2) where C and D are constants. given the inital solution y(0)=1 and y'(0)=1 there are no solutions that exist. Why does this not contradict the Existence and Uniqueness Theorem?

## The Attempt at a Solution

This theorem says that all linear, homogeneous equations have a solution. Since t^2, -2t and 2 are all continuous I don't understand why there is no solution?