Unit and dimension about De broglie wave

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From the de Broglie wave formula we know,
Rhamda=h/p

In actual examples of course the answer would be 'something [meters]'

I am having hardtime to understand how unit of h/mv
[J*s]/[kg]*[m/s] turn into wavelength unit
[m]

I studied the Mass-Energy relation part earlier,
But still can't get the precise way how actually it works and modifes its unit.
 

Answers and Replies

  • #2
Samy_A
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From the de Broglie wave formula we know,
Rhamda=h/p

In actual examples of course the answer would be 'something [meters]'

I am having hardtime to understand how unit of h/mv
[J*s]/[kg]*[m/s] turn into wavelength unit
[m]

I studied the Mass-Energy relation part earlier,
But still can't get the precise way how actually it works and modifes its unit.
What is 1 Joule, expressed in SI base units?
 
  • #3
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213
I am having hardtime how unit of h/mv
[J*s]/[kg]*[m/s] turn into wavelength unit
[m]

I studied the Mass-Energy relation part earlier,
But still can't get the precise way how actually it works and modifes its unit.
Planck's constant is h -its units are joule-sec;
Joule is expressed as energy - its units are kg.m^2.s ^-2 ; so j--s will be kg.m^2.s^-1
so h/ p will be kg.m^2.s^-1 /(kg.m.s^-1 ) = m (in meters) which is the unit of Lambda the wavelength.
 
  • #4
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Planck's constant is h -its units are joule-sec;
Joule is expressed as energy - its units are kg.m^2.s ^-2 ; so j--s will be kg.m^2.s^-1
so h/ p will be kg.m^2.s^-1 /(kg.m.s^-1 ) = m (in meters) which is the unit of Lambda the wavelength.
Thanks!
 

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