Strictly speaking, t here is NOT an angle at all- it measures distance around the unit circle. The unit circle has circumference [itex]2\pi[/itex] so \pi/4 is exactly 1/8 of the entire circle. Since the positive and negative x and y axes divide the circle into 4 equal parts, 1/8 of the circle will be exactly half way between the positive x and y axes and so corresponds to the line y= x. Where does y= x cross the circle x2+ y2= 1?
Another way to get that would be to say that since [itex]\pi/4[/itex] is half of a right angle, if one angle in a right triangle is [itex]\pi/4[/itex] the other angle in a right triangle is also. So the right triangle is an isosceles triangle and the two legs are of equal length. Taking the hypotenuse to be of length 1 and the two legs to be of length x, the Pythagorean theorem, a2+ b2+ c2 becomes x2+ x2= 2x2= 1. Solve for x and then remember that the coordinates of the point are (cos(t), sin(t)).
[itex]\pi/3[/itex] is 1/3 of [itex]\pi[/itex] which corresponds to the total 180 degrees in a triangle. A triangle with all angles [itex]\pi/3[/itex] is an equilateral triangle. Take all sides to have length 1. Drop a perpendicular from the vertex of the triangle to the opposite side and you have two right triangles each with hypotenuse of length 1 and one leg of length 1/2. You can use the Pythagorean theorem to find the length of the other leg and then it is easy to find sine and cosine of the angles [itex]\pi/3[/itex] and [itex]\pi/6[/itex] of the right triangle. Again, the point corresponding to t on the unit circle is (cos(t), sin(t)).