Unit Conversion of CO Concentration in Basement to Micro-gram/m^3

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SUMMARY

The discussion focuses on converting carbon monoxide (CO) concentration from a volume percentage to micro-grams per cubic meter (μg/m³). The measured concentration is 0.1% by volume at 22°C and 1 atm, which equates to 1000 ppm. The ideal gas law (PV=nRT) is utilized to derive the mass of CO in a cubic meter of air, ultimately leading to the calculation of μg/m³. The correct conversion from volume percentage to ppm is confirmed as 0.1% = 1000 ppm.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of unit conversions between percentage and parts per million (ppm)
  • Familiarity with mass concentration calculations
  • Basic principles of gas behavior at standard temperature and pressure
NEXT STEPS
  • Learn how to apply the Ideal Gas Law to different gases under varying conditions
  • Study the conversion of gas concentrations from ppm to mass per volume (e.g., μg/m³)
  • Explore the implications of CO concentration in indoor air quality assessments
  • Investigate the effects of temperature and pressure on gas volume and concentration
USEFUL FOR

Students in chemistry or environmental science, professionals in air quality assessment, and anyone involved in safety monitoring of carbon monoxide levels in residential settings.

saructk
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Homework Statement


The air near a water heater in the basement of an old home is measured for carbon monoxide (CO) and found to contain 0.1% by volume CO at 22*C and 1 atm. Express the CO concentration in the basement in micro-gram/m^3 .

Homework Equations


PV=nRT
P = absolute pressure (atm); V = volume (m3 ); n = mass (mole); R = ideal gas constant = 0.082056 L atm K−1 mol−1 ; and T = absolute temperature (K).

The Attempt at a Solution


The answer said that 0.1% = 10^−3 ppm = 10^3 L CO/ 10^6 L air. But in the book it also has equation to express that {% by volume} x 10000 =ppm. I don't know which one is correct and how to use them.

Beside, after I have calculated the gram of CO, how to relate it with the micro-gram/m^3 ?
thank you.
 
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saructk said:

Homework Statement


The air near a water heater in the basement of an old home is measured for carbon monoxide (CO) and found to contain 0.1% by volume CO at 22*C and 1 atm. Express the CO concentration in the basement in micro-gram/m^3 .

Homework Equations


PV=nRT
P = absolute pressure (atm); V = volume (m3 ); n = mass (mole); R = ideal gas constant = 0.082056 L atm K−1 mol−1 ; and T = absolute temperature (K).

The Attempt at a Solution


The answer said that 0.1% = 10^−3 ppm = 10^3 L CO/ 10^6 L air. But in the book it also has equation to express that {% by volume} x 10000 =ppm. I don't know which one is correct and how to use them.

There's a typo here, either from your textbook or introduced by copying from it.

1 ppm = 1 / 106

0.1% = 103 ppm = 1000 ppm, which is the same as saying that 0.1% CO by volume = 1000 L of CO in 106 L of air

If 0.1% = 1000 ppm, then how many ppm is 1% ?

Beside, after I have calculated the gram of CO, how to relate it with the micro-gram/m^3 ?
thank you.

Take 1 m3 of air at 22°C and P = 1 atm. How many μg of CO are in that cubic meter if the concentration is 0.1% by volume?
 

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