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Unit for the slope of a circular motion relationship

  1. Oct 14, 2008 #1
    1. The problem statement, all variables and given/known data
    so given the formula T=(√((4π^2 m)/Mg)) √l+0
    which is y=mx+b m being (√((4π^2 m)/Mg)) and x being √l

    what is the unit of the slope??





    3. The attempt at a solution
    So the kgs cross out in the mass and we are just left with the units of g which is m/s^2
    since g is on the denominator i got the unit s^2/m

    HOWEVER my problem is that when the slope is multiplied by the x shoudnt it give you the units for y?

    The way I did it it doesent.
     
  2. jcsd
  3. Oct 15, 2008 #2

    tiny-tim

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    Hi Epsillon! :smile:
    erm … it's √g. :redface:
     
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