- #1

hoser1000

- 1

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Equation:

y[n+1] + y[n] = 2x[n]

I am trying to figure out how to solve this equation. I understand the example in the book but I don't understand what to do when it calls a future value (n+1)

I rewrote the equation as:

y[n]=2delta[n]-y[n+1]

When n=0 delta[n] is 1 so:

y[0]=2*1-y[1]<-----This is where I am getting confused. Doesn't y[1] refer to my answer when I use the value n=1? How can I get a solution if each equation will refer to the next future equation? The example in the book uses y[n-1] so for each value of n it refers to the previous answer for y[n].

Any help would be much appreciated!