Unwinding Spool vs. Standard Block

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In a frictionless scenario, both a block and an unwinding spool are pulled by the same tension, leading to the conclusion that they will cross the finish line simultaneously due to equal acceleration. However, the spool possesses greater total kinetic energy because it not only translates but also rotates as it unwinds. The extra work done on the spool arises from the string unwinding, which allows the force to act over a greater distance compared to the block. This additional work contributes to the rotational kinetic energy of the spool. Ultimately, while their translational kinetic energies are equal, the spool has a higher total kinetic energy due to its rotational motion.
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Pulling an Unwinding Spool vs. Standard Block

Homework Statement


This problem is done on a frictionless surface
There is a block pulled by a string with tension T.
Next to it, there is a spool with a string wrapped around it and may unwind. It is pulled with the same tension as System A. The spool is standing on its base, so it slides, and doesn't roll.
The question is whether the block or spool will cross the finish line first, which force does more work, and whether the total kinetic energy (trans. + rot.) are equal.


Homework Equations


conceptual

The Attempt at a Solution


They should cross the line at the same time because it shouldn't matter where the force is applied, the object will still accelerate at the same speed. However, the spool should have more total KE because it is spinning and moving when it crosses the finish line, which also means more work is done on it. What I'm confused about is where the extra work comes from. Does the force on the spool do more work because the string is also unwinding, so the force acts over a greater distance than the force acting on the block?
 
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ssturb said:
They should cross the line at the same time because it shouldn't matter where the force is applied, the object will still accelerate at the same speed.
Right! The same force produces the same acceleration of the center of mass.
However, the spool should have more total KE because it is spinning and moving when it crosses the finish line, which also means more work is done on it.
Right again.
What I'm confused about is where the extra work comes from. Does the force on the spool do more work because the string is also unwinding, so the force acts over a greater distance than the force acting on the block?
Absolutely right!

Someone pulling the string must do a lot more pulling as the spool unwinds, thus they do more actual work on the spool. That extra work goes into rotational KE.
 
Does that mean the translational kinetic energy of the block and spool will be the same?
 
bocobuff said:
Does that mean the translational kinetic energy of the block and spool will be the same?
That's right.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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