1. The problem statement, all variables and given/known data A uniform spool of mass M and diameter d rests on end on a frictionless table. A massless string wrapped around the spool is attached to a weight m which hangs over the edge of the table. If the spool is released from rest when its center of mass is a distance l from the edge of the table, what is the velocity of the weight m when the center of mass of the spool reaches the edge of the table? 2. Relevant equations 3. The attempt at a solution My attempt: I thought of breaking up the problem into two cases and the combining them at the end. case1: Pretend no rotation: With no rotation the spool has forces Tension acting on it. T = Ma The mass attached to the string has forces Tension and gravity. solved for T' = mg - ma Since the acceleration for both we can get to [a = (mg)/(M+m) So, we can get a final velocity of v = √(2*(mg)/(M+m)*l). where I started with vf2 = vi2+2*a*l, l being the displacement of the spool on the table. Case2: Pretend no translation: With no translation, I believe then the Tension and Torque are equal to eachother. Then we can get α = (τ/I). and we can get θ = l/(π*d), What I end up using is the angular kinematics to get ωf= √(2*(τ/I)*(l/(π*d)) So this is my work...am I on the rigth track or completely wrong? And how can I relate these two to get a uniform equation?