Upper trianglar matrix is a subspace of mxn matrices

Click For Summary
SUMMARY

The upper triangular matrices form a subspace of the matrix space ##\mathbb{M}_{m \times n}## over a field ##\mathbb{F}##. This is established by demonstrating that the zero matrix is an upper triangular matrix, and that the sum of two upper triangular matrices remains upper triangular. Additionally, scalar multiplication of an upper triangular matrix by a constant also results in an upper triangular matrix. Therefore, the conditions for a subspace are satisfied.

PREREQUISITES
  • Understanding of matrix theory, specifically the properties of upper triangular matrices.
  • Familiarity with the concept of vector spaces and subspaces in linear algebra.
  • Knowledge of matrix addition and scalar multiplication.
  • Basic understanding of fields in mathematics.
NEXT STEPS
  • Study the properties of vector spaces and subspaces in linear algebra.
  • Learn about different types of matrices, including diagonal and lower triangular matrices.
  • Explore the implications of matrix operations on subspace properties.
  • Investigate examples of other matrix subspaces, such as symmetric and orthogonal matrices.
USEFUL FOR

Students and educators in linear algebra, mathematicians interested in matrix theory, and anyone studying the properties of vector spaces and subspaces.

Mr Davis 97
Messages
1,461
Reaction score
44

Homework Statement


Prove that the upper triangular matrices form a subspace of ##\mathbb{M}_{m \times n}## over a field ##\mathbb{F}##

Homework Equations

The Attempt at a Solution


We can prove this entrywise.

1) Obviously the zero matrix is an upper triangular matrix, because it satisfies the property that whenever ##i > j##, ##A_{ij} = 0##.

2) There are two cases; when ##i \le j## and when ##i > j##.
When ##i \le j## we have that ##(A + B)_{ij} = A_{ij} + B_{ij}##. When ##i > j## we have that ##(A + B)_{ij} = A_{ij} + B_{ij} = 0 + 0 = 0##. Therefore, ##A + B## is still an upper triangular matrix.

3) When ##i \le j## we have that ##(cA)_{ij} = c(A_{ij})##. When ##i > j##, we have that ##(cA)_{ij} = c(A_{ij}) = c(0) = 0##. Therefore, ##cA## is still an upper triangular matrix.

Is this argument enough to show that the upper triangular matrices form a subspace of mxn matrices over a field F?
 
Physics news on Phys.org
Yes.
 
  • Like
Likes   Reactions: Mr Davis 97

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
0
Views
892
Replies
3
Views
1K
Replies
5
Views
2K
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K