- #1

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2 is x and 3 is y, 3 goes to 3.5 and 2.5, i need help with the absolute value of the square root sign 4x+1

- Thread starter afcwestwarrior
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- #1

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2 is x and 3 is y, 3 goes to 3.5 and 2.5, i need help with the absolute value of the square root sign 4x+1

- #2

Gib Z

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Is this what you want?

[tex]\sqrt{4x+1} < \frac{x-2}{2} < \delta[/tex]

[tex]\sqrt{4x+1} < \frac{x-2}{2} < \delta[/tex]

- #3

Gib Z

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[tex]|\sqrt{4x+1}| < \frac{|x-2|}{2} < \delta[/tex]

I hope thats what you want.

- #4

HallsofIvy

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- #5

Gib Z

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To Halls- Look abit closer :p its there.

To OP- I still have no idea what it is you want.

To OP- I still have no idea what it is you want.

- #6

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i should write it exactly

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