- #1

afcwestwarrior

- 457

- 0

2 is x and 3 is y, 3 goes to 3.5 and 2.5, i need help with the absolute value of the square root sign 4x+1

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter afcwestwarrior
- Start date

- #1

afcwestwarrior

- 457

- 0

2 is x and 3 is y, 3 goes to 3.5 and 2.5, i need help with the absolute value of the square root sign 4x+1

- #2

Gib Z

Homework Helper

- 3,352

- 6

Is this what you want?

[tex]\sqrt{4x+1} < \frac{x-2}{2} < \delta[/tex]

[tex]\sqrt{4x+1} < \frac{x-2}{2} < \delta[/tex]

- #3

Gib Z

Homework Helper

- 3,352

- 6

[tex]|\sqrt{4x+1}| < \frac{|x-2|}{2} < \delta[/tex]

I hope that's what you want.

- #4

HallsofIvy

Science Advisor

Homework Helper

- 43,021

- 970

- #5

Gib Z

Homework Helper

- 3,352

- 6

To Halls- Look abit closer :p its there.

To OP- I still have no idea what it is you want.

To OP- I still have no idea what it is you want.

- #6

afcwestwarrior

- 457

- 0

i should write it exactly

Share:

- Last Post

- Replies
- 2

- Views
- 564

- Last Post

- Replies
- 7

- Views
- 424

- Last Post

- Replies
- 6

- Views
- 380

- Last Post

- Replies
- 3

- Views
- 344

- Last Post

- Replies
- 10

- Views
- 353

- Replies
- 2

- Views
- 346

- Replies
- 7

- Views
- 308

- Replies
- 9

- Views
- 296

- Replies
- 3

- Views
- 428

- Replies
- 6

- Views
- 391