Use De Moivre's Theorem to prove this:

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Homework Help Overview

The discussion revolves around using De Moivre's Theorem to prove a trigonometric identity involving complex numbers and the tangent function. The original poster presents a specific equation to demonstrate, noting its relevance to a New South Wales HSC question.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to convert the expression into modulus-argument form but expresses uncertainty about the correctness of this approach. Another participant suggests converting tanθ into sinθ/cosθ as a potential first step.

Discussion Status

Some participants have shared initial steps and transformations, indicating a collaborative effort to explore the problem. The original poster acknowledges the helpfulness of the suggestion, leading to a successful conversion of the expression, although no consensus or final solution has been reached.

Contextual Notes

The problem is framed within the context of a homework assignment, with the stipulation that cosθ ≠ 0, which is an important consideration in the discussion.

aanandpatel
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Use De Moivre's Theorem to show that for any n greater that equal to 1

(1+itanθ)n + (1-itanθ)n =2cosnθ/cosnθ

where cosθ ≠ 0


I tried to approach this by converting into modulus argument form but wasn't really sure if that was correct. It's a common New South Wales HSC question but I couldn't find a solution anywhere. Help would be greatly appreciated :)
 
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The first step would be to convert tanθ into \frac{sin\theta}{cos\theta} and work from there.
 
Thanks a bunch - that helped a lot. Converted it into:
[(secθ)(cosθ+isinθ)]^n + [(secθ)(cosθ-isinθ)]^n and it was easy from there.

Cheers!
 
No problem. Good luck with the HSC, I just finished mine :P
 

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