Use the uncertainty principle for momentum vs. position to e

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SUMMARY

The discussion centers on applying the uncertainty principle to estimate the minimum radius and momentum of an electron in a hydrogen atom, using the energy equation E = p^2/2m - αe^2/r. Participants emphasize the need to understand the relationship between momentum and position, particularly how to relate the uncertainty in position (Δx) to the orbital radius (r) and the uncertainty in momentum (Δp). Key insights include the importance of distinguishing between total energy components and the necessity of conceptual understanding over mere calculation.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically the uncertainty principle.
  • Familiarity with the energy equation for an electron in a hydrogen atom: E = p^2/2m - αe^2/r.
  • Basic knowledge of kinetic and potential energy concepts.
  • Ability to manipulate algebraic expressions involving physical constants and variables.
NEXT STEPS
  • Study the implications of the uncertainty principle in quantum mechanics.
  • Learn how to derive the relationship between momentum and radius in atomic systems.
  • Explore the concept of wave functions and their role in determining electron behavior.
  • Investigate the semiclassical model of atomic structure and its limitations.
USEFUL FOR

Students of quantum mechanics, physics educators, and anyone interested in the foundational concepts of atomic structure and electron behavior in hydrogen atoms.

FlorenceC
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Homework Statement



Please see the attachment for a better picture

The energy of an electron in a hydrogen atom is: E = p^2/2m - αe2/r; where p is the momentum,
r the orbital radius, me the electron mass, e the electron charge, and α the Coulomb constant.
Use the uncertainty principle for momentum vs. position to estimate the minimum radius and the momentum corresponding to this radius.

Homework Equations


E = p^2/2m - αe2/r

I'm not exactly sure what this means conceptually

The Attempt at a Solution


[/B]
Is this a plug and chug? I feel like it's not that simple.
uncertainty for momentum says

delta x * delta p <= h/2π

so do I just plug in p in delta p?
 

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FlorenceC said:
E = p^2/2m - αe2/r

I'm not exactly sure what this means conceptually
The total energy is the sum of kinetic and potential energy.

Is this a plug and chug? I feel like it's not that simple.
uncertainty for momentum says

delta x * delta p <= h/2π

so do I just plug in p in delta p?
Does that work? Did you try? How do you work the ##\Delta x##?
I would suggest understanding the relation before trying random calculations.

If the electron has energy E, then how does the radius depend on the momentum?
Can you relate ##\Delta x## to radius?
 
FlorenceC said:
E = p^2/2m - αe2/r

That's just the total (semiclassical) energy of the electron-nucleus system. The first bit on the left is just the kinetic energy of the electron's orbit, written in terms of momentum instead of velocity. The second bit is the electrostatic potential energy due to the attraction between the electron and the positively charged nucleus. The hydrogen nucleus is just a lone proton, so its charge is +e. Might help to rewrite the whole thing like this:
E = p^2 / 2m + a*(-e)*(+e)/r

FlorenceC said:
Is this a plug and chug? I feel like it's not that simple.

The problem is part visualization and part plugging and chugging. You can't put p's where delta p's go, and same for x. Interpreting the deltas requires some thinking. Remember that delta x and delta p are the deviations observed in measured values of x and p. So how much can x (the electron's horizontal position) vary as the electron orbits the nucleus in a circle of radius r? Likewise, how much can p (the x-component of the electron's momentum) vary in that orbit?
 

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