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Using 18% by weight ammonium hydroxide to make 16ppm aqueous solution
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[QUOTE="Frankenstein19, post: 6854648, member: 584384"] [B]TL;DR Summary:[/B] Used M1V1=M2V2 but am unsure if formula applies I feel like I could use M1V1=M2V2 but the 18% by weight ammonium hydroxide is confusing me so much. Density of ammonium hydroxide 18% is 0.926 g/cm3 18%V1=16mg/L*200L (18mg ammonium/100 mg of total solution) * V1 = 3,200mg ammonium (aq) (18mg ammonium/100 mg of total solution) * V1 = 3,200mg ammonium (aq) V1 = 3,200mg ammonium / 18mg ammonium * 100mg of total solution V1 = 17,777 mg of solution × 1g/1000mg × cm3/0.926g V1 = 1.91 cm3 Is this correct? [/QUOTE]
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Using 18% by weight ammonium hydroxide to make 16ppm aqueous solution
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