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Using Derivative to give a general formula

  • Thread starter tmlrlz
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  • #1
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Homework Statement


a) Find dn/dxn (xn) for n = 1,2,3,4,5. Give the general formula

b) Give the general formula for dn+1/dxn+1 (xn)


Homework Equations





The Attempt at a Solution


a) n = 1 : d/dx (x) = 1
n = 2 :d2/dx2 (x2) = 2
n = 3 :d3/dx3 (x3) = 6
n = 4 :d4/dx4 (x4) = 24
n = 5 :d5/dx5 (x5) = 120

Notice that there is a recurring pattern:
1,2,6,24,120→ multiply the derivative of the previous term by the existing term (2 times 1 = 2, 3 times 2 = 6, 4 times 6 = 24, 5 times 24 = 120)

This is where i'm a little confused, i know what the pattern is and it is a bit hard to explain, however i wrote this out as the general formula:
dn/dxn (xn) = n[dn-1/dxn-1 (xn-1)
Would this be considered right? Or is the general formula suppose to be an arithmetic sequence or a geometric sequence?

b) dn+1/dxn+1 (xn+1)
n = 1 :d2/dx2 (x1) = 0
n = 2 :d3/dx3 (x2) = 0
n = 3 :d4/dx4 (x3) = 0
n = 4 :d5/dx5 (x4) = 0
n = 5 :d6/dx6 (x5) = 0
So then the general formula is:
dn+1/dxn+1 (xn+1) = 0
Once again is this correct or would there be another sequence equation for this like the last one. I am fairly sure that there is not much of an issue of a sequence formula for part b because it will always result in zero but for part a im confused as to if my equation is correct and if it is not, what would the general formula be? Thank you.


The Attempt at a Solution


Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
26,258
618
I think everything you've said is right. In terms of writing a general formula, you might want to check out the definition of the 'factorial' function written "n!".
 
  • #3
33,271
4,976

Homework Statement


a) Find dn/dxn (xn) for n = 1,2,3,4,5. Give the general formula

b) Give the general formula for dn+1/dxn+1 (xn)


Homework Equations





The Attempt at a Solution


a) n = 1 : d/dx (x) = 1
n = 2 :d2/dx2 (x2) = 2
n = 3 :d3/dx3 (x3) = 6
n = 4 :d4/dx4 (x4) = 24
n = 5 :d5/dx5 (x5) = 120

Notice that there is a recurring pattern:
1,2,6,24,120→ multiply the derivative of the previous term by the existing term (2 times 1 = 2, 3 times 2 = 6, 4 times 6 = 24, 5 times 24 = 120)

This is where i'm a little confused, i know what the pattern is and it is a bit hard to explain, however i wrote this out as the general formula:
dn/dxn (xn) = n[dn-1/dxn-1 (xn-1)
Would this be considered right? Or is the general formula suppose to be an arithmetic sequence or a geometric sequence?
The above looks fine. Another way to write the result is to use the factorial.

d2/dx2 (x2) = 2 = 2!
d3/dx3 (x3) = 6 = 3!
d4/dx4 (x4) = 24 = 4!
d5/dx5 (x5) = 120 = 5!

Your sequence 1, 2, 6, 24, 120, ... is neither an arithmetic sequence, in which each term is some constant plus the previous term, or a geometric sequence, in which each term is some constant times the previous term.
b) dn+1/dxn+1 (xn+1)
n = 1 :d2/dx2 (x1) = 0
n = 2 :d3/dx3 (x2) = 0
n = 3 :d4/dx4 (x3) = 0
n = 4 :d5/dx5 (x4) = 0
n = 5 :d6/dx6 (x5) = 0
So then the general formula is:
dn+1/dxn+1 (xn+1) = 0
Once again is this correct or would there be another sequence equation for this like the last one. I am fairly sure that there is not much of an issue of a sequence formula for part b because it will always result in zero but for part a im confused as to if my equation is correct and if it is not, what would the general formula be? Thank you.
 

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