Using Derivatives and Integrals to Find Velocity: Am I doing this right?

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SUMMARY

The discussion centers on using derivatives and integrals to find velocity from the force function F(x) = A + Bx, where A and B are constants and x represents displacement. The user initially attempted to apply Newton's second law (F = ma) but realized that acceleration should be expressed as a function of velocity and displacement. The correct approach involves using the relationship a = dv/dt = (dx/dt)(dv/dx) = v(dv/dx), leading to successful integration to find velocity as a function of displacement.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of basic calculus, specifically integration and differentiation
  • Familiarity with the concepts of velocity and acceleration
  • Ability to manipulate equations involving derivatives and integrals
NEXT STEPS
  • Study the relationship between force, mass, and acceleration in classical mechanics
  • Learn advanced integration techniques for solving differential equations
  • Explore the application of the chain rule in calculus for related rates
  • Investigate the physical interpretation of velocity as a function of displacement
USEFUL FOR

Students in physics or engineering courses, educators teaching mechanics, and anyone interested in the mathematical foundations of motion and dynamics.

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Homework Statement


The function given to me is F(x) = A + Bx.

x is the displacement, F(x) is the force as a function of that displacement, and A and B are constants.

From the function, I'm supposed to find the velocity of the function as a function of x.

We also know that the items which follow this function have mass m.

Homework Equations





The Attempt at a Solution


First I tried using F = ma, giving ma = A + Bx. Then I divided by m on both sides to get a = A/m + (B/m)x.

Then I integrated both sides, to get v = whatever the integral of the RHS is.

But then I realized that a = dv/dt, NOT dv/dx. So integrating with respect to dt doesn't work.

So instead I think I should use a = dv/dt = (dx/dt)*(dv/dx) = v(dv/dx)

And work that into my equation somehow. But I'm having a mental debate with myself about whether I was right the first time... can anyone help?
 
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You are right. Proceed.
 
So my 2nd reasoning is correct, not my first, right?

If I do that it works fine, it's just a simple integration. Thanks!
 

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