Using Faraday's laws to find the induced EMF

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SUMMARY

The discussion centers on the application of Faraday's laws to calculate induced electromotive force (EMF) in a rotating disk scenario. The equation for EMF, \(\epsilon = \frac{d\Phi}{dt} = BA\cos(\theta)\), is highlighted, emphasizing that changes in the magnetic field, area, or angle are typically required to induce voltage. However, the participants clarify that even without these changes, EMF can still be calculated by conceptualizing a closed loop formed by a radius of the disk as it rotates. This approach allows for the determination of the rate of change of the area of the closed loop, which can then be multiplied by the magnetic field intensity (B) to find the induced EMF.

PREREQUISITES
  • Understanding of Faraday's law of electromagnetic induction
  • Familiarity with the concepts of magnetic flux and EMF
  • Knowledge of rotational motion and its effects on magnetic fields
  • Basic skills in dimensional analysis for physics problems
NEXT STEPS
  • Explore the derivation of Faraday's law in different contexts
  • Learn about the implications of changing magnetic fields in electromagnetic systems
  • Investigate the concept of magnetic flux in rotating systems
  • Study practical applications of induced EMF in electrical engineering
USEFUL FOR

Students of physics, electrical engineers, and anyone interested in the principles of electromagnetism and their applications in rotating systems.

L_ucifer
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Homework Statement
A circular disk of radius a is rotating at a constant angular speed w in a uniform magnetic field, B, which is directed out of the plane of the page.
Relevant Equations
\epsilon = \frac{d\Phi } {dt} = BAcos(\theta )
Here is the question:
Screenshot 2022-05-09 at 4.19.55 PM.png

We know the equation \epsilon = \frac{d\phi }{dt} = BAcos(\theta ). This means that the only way we can create an induced voltage is if we change the magnetic field, change the area of the loop in the magnetic field, or change the angle between the normal vector to the surface of the loop and the magnetic field. In this question, neither of those things are changing. Why would there still be induced emf?
 
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L_ucifer said:
\epsilon = \frac{d\Phi } {dt} = BAcos(\theta )
This is true for the EMF around a closed loop. You are being asked for the EMF between the rim and the center of the disc. Since these are spatially separated, there is no closed loop here.

Edit: A lot of the answers can also be discarded solely based on dimensional analysis.
 
Orodruin said:
This is true for the EMF around a closed loop. You are being asked for the EMF between the rim and the center of the disc. Since these are spatially separated, there is no closed loop here.

Edit: A lot of the answers can also be discarded solely based on dimensional analysis.
That makes sense, thanks.
 
Still Faraday's law can be used to calculate the EMF here but we got to have a little imagination on what exactly is the closed loop: Consider a radius of the disk. Then as the disk rotates, imagine that this radius rotate too and the closed loop is the cyclic sector that has the initial position of the radius, the final position of the radius and the in between part of the circumference of disk. Calculate the rate of change of the area of this closed loop as the radius rotate and multiply it by B the intensity of magnetic field..
 

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