Using Gauss' theorem ande exploiting the cylindrical symmetry of the system, show

Click For Summary

Homework Help Overview

The problem involves calculating the electric field generated by a uniformly charged insulating wire using Gauss' theorem, with a focus on cylindrical symmetry. The specific point of interest for the electric field is located at (L/2, L/100).

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply Gauss' theorem and cylindrical symmetry to derive the electric field expression. Some participants question the correct distance (r) to use in the calculations, considering the geometry of the setup.

Discussion Status

Participants are actively discussing the correct interpretation of the distance from the wire to the point of interest. Guidance has been provided regarding the appropriate value of r, indicating a productive direction in the discussion.

Contextual Notes

There is an emphasis on ensuring the correct application of Gauss' theorem and the implications of cylindrical symmetry in the context of the problem. The original poster expresses uncertainty about the next steps in the solution process.

blueyellow

Homework Statement



A wire of length L and negligible transverse dimensions, made of an insulating material, is placed on the x-axis between the origin and the point (L,0). The wire has a uniform line charge density lambda.

using Gauss' theorem and exploiting the cylindrical symmetry of the system, show that the electric field at the point (x,y)=(L/2,L/100) is

E=(100lambda)/(2pi epsilon0 L)

The Attempt at a Solution



integral (S) E.da=E 2 pi r l
Q/(epsilon 0)=(lambda l)/(epsilon0)

2pi r l E=lambda l/epsilon0

E=(1/2 pi r l) (lambda l/epsilon0)
=lambda/(2 pi epsilon0 r)

but I don't know how to proceed from here
 
Physics news on Phys.org


Plug in for the given value of r.
 


oh right! so r is just L/100 because it the wire is along the x axis, so I don't have to do L-L/2?
 


blueyellow said:
oh right! so r is just L/100 because it the wire is along the x axis, so I don't have to do L-L/2?
Right. The point where you want to evaluate the field is at a distance of L/100 from the wire, so that's the value of r you need to use.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 21 ·
Replies
21
Views
4K
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
4
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K