Using Kepler's Law to find speed of a comet in orbit

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Homework Help Overview

The discussion revolves around calculating the speed of a comet in elliptical orbit using Kepler's laws. The original poster presents a scenario involving a comet's speed at two different distances from the sun and attempts to apply Kepler's laws to find the speed at the second distance.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the application of Kepler's laws, particularly questioning the relevance of the specific law used for the problem. Some suggest using conservation of energy instead of solely relying on Kepler's laws. Others raise concerns about the units of measurement and the need for clarity in the problem statement.

Discussion Status

There is an ongoing exploration of different approaches to the problem, with some participants offering guidance on using conservation of energy and others reflecting on the implications of Kepler's laws. The discussion indicates a lack of consensus on the best method to apply, but productive suggestions have been made.

Contextual Notes

Participants note the need for clarity regarding the units of measurement and the specific requirements of the problem statement, which may influence the approach taken. There is also mention of confusion regarding the application of different laws of motion in the context of the problem.

johannaposey
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Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 2.5×104 when at a distance of 2.3×1011 from the center of the sun, what is its speed when at a distance of 5.9×1010 .
Using Kepler's Law T2 is proportional to R3
T2/R3 is a constant (C)
-->T= (2*\pi*R)/v -->T2= (4*\pi2*R2)/v2

therefore
C= (4*\pi2)/(R*v2)

since
4*\pi2 is a constant C= 1/(R*v2)

therefore
R1*(v1)2=R2*(v2)2

Plugging in the variables, I got 4.93x104, but that answer was wrong. Why?
 
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johannaposey said:
Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 2.5×104 when at a distance of 2.3×1011 from the center of the sun, what is its speed when at a distance of 5.9×1010 .

Using Kepler's Law T2 is proportional to R3
T2/R3 is a constant (K)
-->T= (2*\pi*R)/v -->T2= (4*\pi2*R2)/v2

therefore
K= (4*\pi2)/(R*v2)

since
4*\pi2 is a constant K= 1/(R*v2)

therefore
R1*(v1)2=R2*(v2)2

Plugging in the variables, I got 4.93x104, but that answer was wrong. Why?
Hello johannaposey. Welcome to PF !

Aren't there three of Kepler's Laws ?

The one you used relates the period for the whole orbit and the orbits average distance from the Sun.

You have information regarding the comet at two particular places in its orbit. Use one of the other two laws.
 
Also, what are the units? Furlongs and fortnights? Always be sure to specify the units!
 
Every distance is in meters. I assume I will need to use Kepler's second law (stating that a line joining the planet and the sun sweeps out equal areas during a time interval). Is this right? If it is how do I use it. I don't have the orbital velocity.
 
Does the problem statement specifically direct you to use Kepler's laws to to solve it? I'd be more inclined to look at conservation of energy.
 
I tried conservation of energy, but got stuck. I tried U1=K1+K2+U2 Where U1 is the potential energy of the system at the beginning (Gm1m2/r1) K1 is the kinetic energy of the smaller mass (1/2 m1v1^2) K2 is the kinetic energy of the larger mass (1/2 m2v2^2) and U2 is the potential energy at the second radius (Gm1m2/r2). After I did that tI had two unknowns v1 and v2.
 
johannaposey said:
I tried conservation of energy, but got stuck. I tried U1=K1+K2+U2 Where U1 is the potential energy of the system at the beginning (Gm1m2/r1) K1 is the kinetic energy of the smaller mass (1/2 m1v1^2) K2 is the kinetic energy of the larger mass (1/2 m2v2^2) and U2 is the potential energy at the second radius (Gm1m2/r2). After I did that tI had two unknowns v1 and v2.

You only need to consider the KE and PE of the comet; the Sun is taken to be a stationary object since its mass is much, much greater than that of the body in orbit. If m is the comet's mass and M the Sun's mass, then what is called the 'specific mechanical energy' for the orbit is given by
$$\xi = \frac{v^2}{2} - \frac{G M}{r}$$
and is a constant of the motion.
 
Oops! I was getting two questions confused. I don't know why I didn't try that earlier. I've got the right answer now. Thank you!
 
johannaposey said:
Oops! I was getting two questions confused. I don't know why I didn't try that earlier. I've got the right answer now. Thank you!
What did you get for the answer?
 

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