Using left endpts help with squr(3i/16) how to get the i out

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SUMMARY

The discussion focuses on approximating the area under the curve of the function y = √(x + 2) over the interval [1, 4] using left endpoints with n = 16. The change in x is calculated as 3/16, and the x-sub-i values are determined using the formula x-sub-i = x-sub-0 + i(change in x). The user encounters difficulty in manipulating the summation involving the variable i and is advised to multiply the function values by the width of the rectangles and sum them up to complete the approximation.

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Homework Statement


i am have to approximate the area under the curve using left endpoints.

Homework Equations


y= squr(x+2) on [1,4], n =16

The Attempt at a Solution


i have the change in x to be 3/16 using (b-a)/n i also found my xsubi to be (1+3i/16) using xsubi = xsubo + i(chang in x). then i got (3/16) E (squr(1+(3i/16)+ 2)) i am stuck on how to get the i out to then apply the formula n(n+1)/2 or n(n+1)(2n+1)/6.

Thank you ahead of time.

another question similar problem but i get stuck after i don't know how to take the i out of cos(pi(i)/100) i tried multiplying by sec but i still don't get the right answer. do i multiply by sec? to get the i out of cos(pi(i)/100)?
 
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You can't apply those summations to this one, the first one applies to linear functions and the second to quadratics, but for this one all they want is to use left rectangles.

You know the x values you have to set up the rectangles at, and the width (3/16). Now all you have to do is multiply each by f(x) at the point you set up the rectangle at, them sum them all up. Simple, but tedious process.
 

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