Using potential energy graph, find particle turning point

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To find the turning point of a particle using potential energy graphs, the total mechanical energy (Emec) must equal the potential energy (PE) at that position. The initial kinetic energy (KE) was calculated as 28.125 when the particle starts at x = 4. The discussion highlights the need to derive the position where energy equals Emec, suggesting the use of force derived from the potential energy function. The participant expresses feeling overwhelmed with upcoming exams and assignments but confirms they have solved the problem. Understanding the relationship between energy and position is crucial for determining the turning point.
isukatphysics69
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Homework Statement


help1.PNG


Homework Equations


Emec - PE = KE

The Attempt at a Solution


When particle starts at x = 4 KE = .5(.25)(225) = 28.125
Energy of system = 28.125
I don't have anything with position here so i am unsure how to find what position that the energy will be equal to the Emec and turn the particle around
 

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I think i need to use force here and force is dPE(X)/dx
 
isukatphysics69 said:
KE = .5(.25)(225)
Check the mass.
isukatphysics69 said:
how to find what position that the energy will be equal to the Emec
That's what the graph is for.
 
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yes i solved it i should have marked solved i am not careful i am overwhelmed i have final exam Tuesday and a million physics homeworks and presentations and stuff omg
 

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