Using Riemann Upper sums to solve limits

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SUMMARY

The discussion focuses on using Riemann Upper sums to compute limits in integral calculus, specifically the expression \(\int^1_0 f(x) dx = \lim_{n\to \infty} \frac{1}{n} \sum_{k=1}^{n} f\left(\frac{k}{n}\right)\). The challenge presented is identifying the function \(f(k/n)\) to express it in terms of \(f(x)\). Participants agree that there is no general method for this identification other than through inspection, emphasizing the reliance on recognizing patterns in specific examples.

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Gib Z
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I often see people use the Riemann definition of the integral to solve a certain limit-series computation, but they usually just skip a step that I can follow one way but not the other. Given the integral, I can see the limit-series that comes from it, but when trying to find the integral from the limit-series I have a problem.

For example, over the interval a=0 and b=1, [tex]\int^1_0 f(x) dx = \lim_{n\to \infty} \frac{1}{n} \sum_{k=1}^{n} f\left(\frac{k}{n}\right)[/tex] using Riemann Upper sums.

So basically If required to somehow work out [tex]f(k/n) = something[/tex], so that I can re-express it in terms of f(x). So i guess the question is, does anyone know a general method to spot the function of k/n, as to find f(x) ?
 
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I don't believe is any, rather than pure inspection.

In most examples I've seen, the sum can be worked to be on the most common form

[tex]\lim_{\Delta P\rightarrow 0}\sum_{n=0}^\infty f(x_i^*)(x_{i+1}-x_i),[/tex]

where [itex]P=\{x_0,...,x_n,...\}[/itex] and [itex]x_i^* \in (x_i,x_{i+1})[/itex], so its easier to spot the [itex]f[/itex].
 
Damn I was hoping that wouldn't be the answer :( Thanks
 

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