Using sum difference derivative instead of prodict rule?

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Discussion Overview

The discussion centers around the differentiation of a polynomial function expressed as a product of binomials and a trinomial. Participants explore whether it is appropriate to use the sum rule after simplifying the product or to apply the product rule directly.

Discussion Character

  • Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant suggests that multiplying the first two binomials and then applying the sum rule could simplify the differentiation process.
  • Another participant agrees that either method—multiplying out the terms or using the product rule—will yield correct results, emphasizing the importance of choosing the simpler approach.
  • A third participant provides the derivative using the product rule, illustrating the application of the formula without simplifying the expression first.
  • Some participants express uncertainty about the necessity of simplification before differentiation, indicating that both approaches are valid.

Areas of Agreement / Disagreement

Participants generally agree that both methods of differentiation are valid, but there is no consensus on whether one approach is definitively better than the other.

Contextual Notes

Some participants highlight the potential complexity of the problem depending on the chosen method, but no specific limitations or assumptions are fully resolved.

Nano-Passion
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Let us say we have this:

[tex]f(x)=(x^3-x)(x^2+2)(x^2+x-1)[/tex]

Would it be equally correct to multiply the first two binomials, and then taking that and multiplying by the last tri-nomial; and then using the sum rule? It seems perfectly fine (and much simpler!) but I want to make sure I am not violating anything here. It seems like a longer problem to use the product rule twice.
 
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Either way will work. Just guess what is most simple and start in.
 
Since you are talking about the derivative, I see no reason to multiply it out at all:
(fgh)'= fgh'+ fg'h+ f'gh.
[tex]((x^3−x)(x^2+2)(x^2+x−1))'= (x^3- x)(x^2+2)(2x+1)+ (x^3-x)(2x)(x^2+X-1)+ (3x-1)(x^2+2)(x^2+x-1)[/tex]
 
HallsofIvy said:
Since you are talking about the derivative, I see no reason to multiply it out at all:
(fgh)'= fgh'+ fg'h+ f'gh.
[tex]((x^3−x)(x^2+2)(x^2+x−1))'= (x^3- x)(x^2+2)(2x+1)+ (x^3-x)(2x)(x^2+X-1)+ (3x-1)(x^2+2)(x^2+x-1)[/tex]
True, I just figured I should simplify that more, so I wanted to do the other route. But now I see you don't have to simplify that more.

lurflurf said:
Either way will work. Just guess what is most simple and start in.

Okay, never hurts to be completely sure. :)
 

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