Using the equation intensity = power/cross-sectional area

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Homework Help Overview

The discussion revolves around calculating the intensity of light emitted from a 100W lamp, modeled as a point source, and the relationship between intensity, power, and surface area. The subject area includes concepts from optics and geometry, particularly regarding the distribution of light over a spherical surface.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the formula for intensity and its dependence on the surface area of a sphere. Questions arise regarding the terminology of "cross-sectional area" versus "surface area" and how it applies to the scenario of light distribution.

Discussion Status

The discussion is active with participants clarifying the definitions of surface area and cross-sectional area in the context of the problem. Some guidance has been offered regarding the interpretation of the formula, but multiple viewpoints on the terminology are being examined.

Contextual Notes

There is an ongoing debate about the appropriate use of terms related to surface area in the context of light intensity calculations, particularly in relation to the geometry of the situation described.

John421
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Let's say we have the problem: A 100W lamp emits light in all directions. Assuming that the lamp is a point source, calculate the intensity of the radiation 1m away from the lamp.

The surface area of a sphere is :4*Pi*r2
intensity = power/cross-sectional area
The answer is intensity = 100w/4Pi = 7.96

Now what confuses me is that the answer is derived by intensity = power/surface area of the shape the wave makes when it spreads out.

Shouldn't cross-sectional area be the cross-sectional area of a sphere?
I don't see how 4*Pi*r2 is the cross-sectional area in this case.
 
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4 pi r2 is the surface area of a sphere. Your light will be distributed uniformly over this area.
 
But then why does the formula say cross-sectional area instead of surface area?
 
This is the cross-section of the light with your sphere. It happens to be the whole sphere as you have a point-charge radiating in all directions.
 
If the question were to ask what the intensity of the light was at a screen 1m away from your light source, then you would use the surface area of that screen, not the surface area of your light source (just to be clear on what surface area you are using -- not the surface area of your light source). I just want to ensure you know that the equation uses the cross-sectional area (of the light) interchangeably with the surface area of the *thing* that the light is hitting.
 

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