Using the inverse hyperbolic tangent function to solve ODE

[bitrex]

Homework Statement

Hi all. I have to solve the differential equation \frac{dv}{dt} = g(1 - \frac{\rho}{g}v^2).

The Attempt at a Solution

Apparently the solution should involve the inverse hyperbolic tangent function - with the equation in this form it should just be separable, correct? However, when separating variables I have to integrate the function \frac{dv}{1-\frac{\rho}{g}v^2} which I am not sure how to go about. I think a substitution of some kind? Any tips would be appreciated.

 

[HallsofIvy]

Partial fractions: 1-\frac{\rho}{g}v^2= (1- \sqrt{\frac{\rho}{g}}v)(1+ \sqrt{\frac{\rho}{g}}v).

 

[Dick]

Or v=sqrt(g/rho)*tanh(u), if you want to stick with the hyperbolic function approach. You'll get the same answer, though it will look different.

 

[bitrex]

I see it now. Thanks guys!