I have this equation 1/(r^2+l^2)^(3/2) and I need to integrate it quickly. My first thought is using this integral formula 1/(1+x^2)^(3/2)=x/sqrt(1+x^2) but how exactly do I get my equation into that form?(adsbygoogle = window.adsbygoogle || []).push({});

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# Using trig identity to simplify?

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