Using u substitution, which of the following is equivalent to this integral?

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The integral ∫(2x + 1)1/2dx can be transformed using the substitution u = 2x + 1, leading to (1/2)*∫u1/2du. When changing the limits of integration, substituting x = 0 and x = 2 gives new limits of u = 1 and u = 5. However, it's noted that changing the limits is not necessary; one can evaluate the indefinite integral and then apply the original limits. The discussion clarifies the correct approach to handling limits during substitution in definite integrals. Understanding this process is crucial for accurately solving integrals using u substitution.
lude1
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Homework Statement



Using the u substutituion u = 2x + 1, ∫(2x + 1)1/2dx (when x goes from 0 to 2) is equivalent to?

Answer: (1/2)*∫(u)1/2du (when x goes from 1 to 5)


Homework Equations





The Attempt at a Solution



If u is 2x + 1, then du = 2dx. Thus, I get

(1/2)*∫(u)1/2du (when x goes from 0 to 2)​

The only problem is where did the x goes from 1 to 5 come from? Did I do something wrong, or is the AP packet wrong?
 
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For a question like this, when you use substitution to solve a definite integral and have it in a form with u in it, you need to have the two limits in terms of u as well, not x.

So in this example, the limits are 0 to 2 and you know that u = 2x + 1. Just substitute in x = 0 and x = 2, and it gives you the new limits of 1 and 5.
 
Last edited:
Oh, yes, you are right. I forgot that in order for my answer to be right, it had to be (1/2)*∫(2x + 1)1/2du (when x goes from 0 to 2).

Thanks!
 
lude1 said:
Oh, yes, you are right. I forgot that in order for my answer to be right, it had to be (1/2)*∫(2x + 1)1/2du (when x goes from 0 to 2).

Thanks!
That should be (1/2)*∫(2x + 1)1/2dx.

It's not necessary to change the limits of integration when you do a substitution. You can work with the indefinite integral, make the substitution, get your antiderivative, undo your substitution, and then evaluate your antiderivative at the original limits.
 
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