Undergrad Valid local explanation of Bell violations? (Pegg et al., 1999; 2008)

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Question of the plausibility of a local explanation of bell violating entanglement specifically in the Kocher-Commins experiment using quantum retrodiction.
These papers by Pegg et al. (doi: 10.1016/j.shpsb.2008.02.003 [section 4]; https://www.researchgate.net/publication/230928426_Retrodiction_in_quantum_optics [section 3.2]) seem to show that photon Bell correlations can be inferred using quantum theory in a manner that is compatible with locality by performing quantum retrodiction (i.e. inferring information about the past: e.g. https://doi.org/10.3390/sym13040586; more papers at end) where they evolve backward from Alice's measured outcome, and then forward again to Bob's. They only specifically model the Kocher-Commins experiment, where retrodicting about an atom-field state in the past tells you the state that Bob's photon was emitted as, and do not seem to have generalized beyond this specific example. Nonetheless, I think there is a general force to the argument that if quantum theory itself actually allows you to retrodict a definite state at the time of a locally-mediated correlating interaction, then non-local influences arguably seem redundant for producing the correct probabilities in entanglement scenarios similar to the one in Pegg et al.

If valid, then clearly the retrodiction from a measurement outcome assigns different states in the backward-in-time direction compared to what the corresponding regular forward-in-time description would start out with, and this looks retrocausal. But at the same time, the quantum retrodiction as described above is just another equivalent way of formulating the same empirical content of quantum theory, and related to regular quantum prediction by Bayes' theorem such that it would always be possible to derive or express backward-in-time probabilities entirely in terms of regular forward-in-time ones. One might then ask whether interpretations in which the wavefunction isn't real avoid any purported need for retrocausation (for instance, in Barandes' indivisible approach, the wavefunction is more or less reducible to a stochastic process description which then doesn't really leave any explicit indicators of retrocausality without importing additional ontological interpretation into the description). It might be worth noting that though the 2008 Pegg et al. paper uses explicit retrocausal language, the later review https://doi.org/10.3390/sym13040586 seems to be much more open to the non-reality of the wavefunction, and at the very least explicitly suggests that collapse should not be seen as a physical process.

I'm aware that this "Parisian zig-zag" explanation has been described by various others; but from what I have skimmed, others don't seem to be explicitly suggesting that it is actually inherent in quantum theory in the same way as these papers. I guess the most important criticisms of this would be whether their description is actually truly a valid way of using quantum theory to explain those correlations, and whether their type of description broadly-speaking can work for any entanglement experiment. Again, I'm inclined to think that if it is valid, it may not be strictly necessary that the explanation is retrocausal, at least with regard to the probabilities. But obviously maybe there are other arguments I'm not thinking of for retrocausality here.

More quantum retrodiction papers:

https://eprints.gla.ac.uk/334605/;
arXiv:1107.5849v4 [e.g. section IVC];
arXiv:2010.05734v2 [e.g. section 2];
https://doi.org/10.1098/rsta.2023.0338; https://strathprints.strath.ac.uk/5854/;
arXiv:quant-ph/0106139;
arXiv:quant-ph/0207086v1
 
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When I bring up that "researchgate" link, I get the abstract and the references - but not the full article.

From what I gather, in that paper they are saying that a retrodiction can be made based on one measurement that infers conditions that will affect the other measurement. Fine enough - but that retrodiction cannot be made until that first measurement has been made - and the results of that first measurement (and thus the retrodiction) can be based on events not local to the second measurement.

In other words, the retrodiction itself is non-local to the second measurement. Although the second measurement may be within the light cone of conditions described by the retrodiction, it is not within the light cone of the retrodiction itself.
 
.Scott said:
When I bring up that "researchgate" link, I get the abstract and the references - but not the full article.
Thats strange, it gives me as of now both the full article on the page and a pdf link. I can only offer a different link:

https://scholar.google.co.uk/scholar?cluster=11813849258704424520&hl=en&as_sdt=0,5&as_vis=1

.Scott said:
retrodiction cannot be made until that first measurement has been made - and the results of that first measurement (and thus the retrodiction) can be based on events not local to the second measurement.
This is fair though my counter would be that:

1) for all intents and purposes, that first measurement (e.g. Alice) is going to have a random outcome which wouldn't change whether performed simultaneously alongside Bob's or Bob's had never been measured at all or anything else.

2) It seems to me that their retrodiction from that measurement outcome would be the same whether the measurement is on an entangled state or a single-particle state on its own.

Its then not obvious that the explanation depends on anything else going on non-locally, just the first measurement outcome and the atom field-state being retrodicted back to in the past which locally produced the two photon states in a correlated manner, the second of which going off to Bob.
 
iste said:
their retrodiction from that measurement outcome would be the same whether the measurement is on an entangled state or a single-particle state on its own.
If that's true, then their retrodiction can't make correct predictions, because it can't account for the presence of the Bell inequality-violating correlations in the first case, and their absence in the second.
 
PeterDonis said:
If that's true, then their retrodiction can't make correct predictions, because it can't account for the presence of the Bell inequality-violating correlations in the first case, and their absence in the second.
What I mean is that retrodicting back-in-time from the polarization measurement outcome always retrodicts the polarization state associated with that outcome. If you measure H, it retrodicts H back-in-time if the scenario was a measurement on a single-particle state. In the entanglement case, they are using this to retrodict about an atom-field state in the past which emitted another photon correlated to the first, and will produce the correct Bell violating conditional probabilities when you measure that second single particle state that was emitted.
 
iste said:
retrodicting back-in-time from the polarization measurement outcome always retrodicts the polarization state associated with that outcome.
Which is not an entangled state, so, as I said, this can't possibly make correct predictions about Bell inequality violations, which arise from entangled states.

iste said:
If you measure H, it retrodicts H back-in-time if the scenario was a measurement on a single-particle state.
This contradicts what you said before; before you said "always", now you're saying "only if the scenario was a measurement on a single-particle state". But knowing whether or not the measurement was on a single-particle state requires information not local to the measurement, as @.Scott has already pointed out.

iste said:
In the entanglement case, they are using this to retrodict about an atom-field state in the past which emitted another photon correlated to the first, and will produce the correct Bell violating conditional probabilities when you measure that second single particle state that was emitted.
In other words, they can't predict Bell inequality violating correlations at all--they have to have them measured first, and then claim to "retrodict" them. Sounds pointless to me.
 
Last edited:
iste said:
1) for all intents and purposes, that first measurement (e.g. Alice) is going to have a random outcome which wouldn't change whether performed simultaneously alongside Bob's or Bob's had never been measured at all or anything else.
Clearly, if you start with that presumption, everything is local.
But that presumption is wrong.
If it was right, there would be nothing to talk about - because that is the way we all "naturally" expect things to work.

The key to understanding the Bell inequality is to understand how one can demonstrate that that "common sense" presumption is wrong.

And the way that it is done is this:
1) Flip Bob's detector up-side-down so that it is rotated 180 degrees compared to the measurements made by Alice. This makes the rest of the experiment easy to explain.
2) Make 10,000 measurements and compare the Alice/Bob results. They will all match. Basically, each entangled particle is the up-side-down version of its copy.
3) Now rotate Bob's device another 5 degrees and make another 10,000 measurements. The typical result will show about 38 mis-matches - less than half a percent.
4) Now rotate Bob's device another 5 degrees (a total of 10 degrees) and make another 10,000 measurements. The typical result will show about 152 mis-matches.

And that's where the problem comes in. If you start with 0 differences, rotate by 5 degrees and get 38 differences. Then rotating another 5 degrees should give you another 38 difference at most. A total of 76. Somehow the measurement results are directly affected by the angular difference in the measurement settings selected by Alice vs. Bob. And that difference is not available to either Alice or Bob when the measurements are being made.
 
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PeterDonis said:
now you're saying "only if the scenario was a measurement on a single-particle state".
I meant it does the same in both cases once you measured the outcome and evolve back from it.
PeterDonis said:
Which is not an entangled state, so, as I said, this can't possibly make correct predictions about Bell inequality violations, which arise from entangled states.
The gist of the mechanism is you measure H, retrodict H back at the source. Retrodicting that a H photon was emitted implies another V photon was also emitted due to the atom description at source. Propogating the V photon forward-in-time, staying the same, and then measuring it will give you the cos^2 (θ-θ) conditional probability because Bob has measured the V photon with a cos^2 probability of Bob's analyzer orientation minus the V photon orientation. From the description above, the V photons orientation is conditioned on the other H photon orientation which is the same orientation as Alice's analyzer, which means Bob's cos^2 measurement probability is equivalent to Bob's analyzer orientation minus Alice's analyzer orientation. If you were to somehow modify the correlation at source by 90° and/or -θ, you will get the other three Bell state correlations using this same description.


PeterDonis said:
In other words, they can't predict Bell inequality violating correlations at all--they have to have them measured first, and then claim to "retrodict" them. Sounds pointless to me.
Well, to me, unless the retrodiction is just wrong, it makes nonlocal influence look redundant.
 
iste said:
I meant it does the same in both cases once you measured the outcome and evolve back from it.
I'm not sure what you mean by "the same".

iste said:
The gist of the mechanism is you measure H, retrodict H back at the source.
You're contradicting yourself again. If this is done regardless of whether the system was originally prepared as an entangled state or not, you obviously can't get things right in both cases. But if it's only done if the system was not originally prepared in an entangled state, then what you're saying here makes no sense.

iste said:
Retrodicting that a H photon was emitted implies another V photon was also emitted due to the atom description at source.
Only if the system was originally prepared in an entangled state. If it wasn't, retrodicting H for one photon tells you nothing at all about the other.

iste said:
Propogating the V photon forward-in-time, staying the same, and then measuring it will give you the cos^2 (θ-θ) conditional probability because Bob has measured the V photon with a cos^2 probability of Bob's analyzer orientation minus the V photon orientation.
What do you mean by "the V photon orientation"?

iste said:
From the description above, the V photons orientation is conditioned on the other H photon orientation
This makes no sense to me, unless it's just another way of saying that the two photons are prepared in a particular entangled state.
 
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.Scott said:
Clearly, if you start with that presumption, everything is local.
But that presumption is wrong.
If it was right, there would be nothing to talk about - because that is the way we all "naturally" expect things to work.

The key to understanding the Bell inequality is to understand how one can demonstrate that that "common sense" presumption is wrong.

And the way that it is done is this:
1) Flip Bob's detector up-side-down so that it is rotated 180 degrees compared to the measurements made by Alice. This makes the rest of the experiment easy to explain.
2) Make 10,000 measurements and compare the Alice/Bob results. They will all match. Basically, each entangled particle is the up-side-down version of its copy.
3) Now rotate Bob's device another 5 degrees and make another 10,000 measurements. The typical result will show about 38 mis-matches - less than half a percent.
4) Now rotate Bob's device another 5 degrees (a total of 10 degrees) and make another 10,000 measurements. The typical result will show about 152 mis-matches.

And that's where the problem comes in. If you start with 0 differences, rotate by 5 degrees and get 38 differences. Then rotating another 5 degrees should give you another 38 difference at most. A total of 76. Somehow the measurement results are directly affected by the angular difference in the measurement settings selected by Alice vs. Bob. And that difference is not available to either Alice or Bob when the measurements are being made.
The papers infer the correct Bell correlation in a manner that looks local, or doesn't require distamt communication in the.inference steps, only using quantum theory. How it does it is the retrodiction appears to violate statistical independence because as far as I can tell, evolving back from a measured polarization outcome results in that same measured state in general when we have no information about the past.
 
  • #11
iste said:
a manner that looks local
I'm not sure how it "looks local" given that, as @.Scott has already pointed out, the information used does not all lie in a single past light cone.
 
  • #12
iste said:
it makes nonlocal influence look redundant.
Again, I'm not sure why. Consider an obvious "hidden variable" interpretation of the retrodiction: measuring H for the first photon sends the H information back in time along the first photon's worldline to the event where the two photons are prepared, and then forward in time along the second photon's worldline to the measurement of the second photon. (This is somewhat similar to John Cramer's transactional interpretation.) Is this "local"? I don't see how. "Local" doesn't allow backwards in time propagation. And any other way of "explaining" how the retrodiction works (assuming it does work) will have the same problem.
 
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  • #14
PeterDonis said:
I'm not sure how it "looks local" given that, as @.Scott has already pointed out, the information used does not all lie in a single past light cone.
I think it does though because the explanation only relies on a random measurement outcome and what that retrodicts backward-in-time in a manner which only really depends on that outcome.

PeterDonis said:
Again, I'm not sure why. Consider an obvious "hidden variable" interpretation of the retrodiction: measuring H for the first photon sends the H information back in time along the first photon's worldline to the event where the two photons are prepared, and then forward in time along the second photon's worldline to the measurement of the second photon. (This is somewhat similar to John Cramer's transactional interpretation.) Is this "local"? I don't see how. "Local" doesn't allow backwards in time propagation. And any other way of "explaining" how the retrodiction works (assuming it does work) will have the same problem.

Well if Alice's photon is not telling Bob's photon what to do across space instantaneously, but instead they are both being told what to do at the source, and the correlation is preserved because the states don't change during time-evolution - that seems local to me. The question for this purportex explamatiom i guess is whether backward propagation really is something like "time-travel".
 
  • #15
iste said:
Well if Alice's photon is not telling Bob's photon what to do across space instantaneously, but instead they are both being told what to do at the source, and the correlation is preserved because the states don't change during time-evolution - that seems local to me. The question for this purportex explamatiom i guess is whether backward propagation really is something like "time-travel".
It is, it is retrocausality. You might say it is "local" if you wish but you are still breaking causality which seems as or more problematic than "nonlocality" (whatever that means).
 

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