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Value of second derivative at a given point?

  1. Apr 30, 2012 #1
    I'm not sure how to evaluate the second derivative

    d2y/dx2 = (4(dy/dx) -12x^2 -12y^2(dy/dx)^2)) /(4y^3 - 2x)
    AT A GIVEN POINT (1,1). The answer is -14 not sure how they got it.

    Final exam this friday would appreciat e answers very much!
     
  2. jcsd
  3. Apr 30, 2012 #2

    tiny-tim

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    hi ashina14! :smile:

    (try using the X2 button just above the Reply box :wink:)

    what is the complete question? :confused:
     
  4. Apr 30, 2012 #3
    Didn't occur to me that the value of dy/dx would play a role. But it is -1 and now I know I just need to substitute it in this equation wherever appropriate! Stupid question! :P
     
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