Van der waals attraction between 1-D wires

Click For Summary
SUMMARY

The discussion focuses on estimating the van der Waals interaction between two infinitesimally thin 1-D wires of equal length L, positioned at a mutual distance d. The interaction is modeled using the equation u(r) = -C/r^6, where C is a constant. The user successfully derived the interaction energy contribution from one atom on a wire to all atoms on the other wire, resulting in the total interaction energy expressed as σL U(r), where σ represents the atomic density along the wires. Clarification was sought regarding the configuration of the wires and the implications of their mutual distance.

PREREQUISITES
  • Understanding of van der Waals forces and their mathematical modeling
  • Familiarity with integral calculus for evaluating interaction energies
  • Knowledge of 1-D systems in physics
  • Concept of atomic density in material science
NEXT STEPS
  • Research the implications of wire configuration on van der Waals interactions
  • Study the effects of atomic density on interaction energy calculations
  • Explore advanced topics in quantum mechanics related to 1-D systems
  • Learn about numerical methods for evaluating integrals in physics problems
USEFUL FOR

Students and researchers in physics, particularly those studying intermolecular forces, 1-D systems, and van der Waals interactions in materials science.

CAF123
Gold Member
Messages
2,918
Reaction score
87

Homework Statement


Consider two infinitesimally thin (i.e 1-D) wires of equal length ##L##, and at
mutual distance ##d##.
Consider the two configurations shown in attachment
Estimate the van der Waals interaction between the wires, for ##d \gg L##, in the two situations

where: (i) the wires are parallel and in register, as on left and (ii) the wires lie on parallel
planes and are in the ''cross'' configuration as on the right.

Homework Equations


VDW attraction between atoms modeled by ##u(r) = - C/r^6, C## a constant.

The Attempt at a Solution


Set up a coordinate system with ##z## axis coinciding with the wire with origin midway. The attraction between the atom at ##z=0## on one wire and an arbritary atom at some distance ##\sqrt{d^2 + z^2}## is therefore ##u(z) = -C/(z^2 + d^2)^3##. This atom at ##z=0## therefore contributes ##U(r) = \int_{-L/2}^{L/2} u(z) dz##, i.e the interaction energy contributed from this atom on one wire and all others on the other. Now how should I proceed to get the total interaction energy due to all atoms? I wasn't specified the atom density along the wires.

I can't make sense of the mutual distance of the wires being a distance ##d## apart in the second configuration.

Thanks.
 

Attachments

  • VDW.png
    VDW.png
    189 bytes · Views: 451
Physics news on Phys.org
The question was updated with the atomic density being ##\sigma##, so my answer for the total interaction energy between the wires is ##\sigma L U(r)## Is it correct?
 
Can anyone help?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
6
Views
2K
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 24 ·
Replies
24
Views
8K