What is the molecular diameter of hydrogen using Van der Waals coefficients?

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SUMMARY

The molecular diameter of hydrogen, calculated using Van der Waals coefficients, is determined to be 0.438 nm. This calculation utilizes the constant b, which represents molecular volume, and the formula V = b/N, where N is Avogadro's number. The Van der Waals coefficients for hydrogen are a = 0.244 atm L²·mol⁻² and b = 26.6 L·mol⁻¹. The constant a, while relevant for attractive forces, does not impact the calculation of molecular diameter in this context.

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  • Knowledge of Avogadro's number
  • Familiarity with molecular volume concepts
  • Basic geometry of spheres
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mikeclinton
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Homework Statement


Calculate the molecular diameter of hydrogen, assuming the spherical shape on the basis of van der Waals coefficients.

Van der Waals Coefficients for hydrogen
a = 0.244 atm L2.mol-2
b*103 = 26.6 L.mol-1

Homework Equations


Not indicated in the problem but I would think the Van der Waals equation of state.

The Attempt at a Solution


For hydrogen:
Since the constant b is an indication of molecular volume, it could be used to estimate the radius of an atom or molecule, modeled as a sphere. This leads to the following estimate of radius:

V = b/N = (26.6 x 10-6)/6.02*1023 (I have first converted b unit to m3/mol)
V = 4πr3/3
which gives r = 0.219nm
corresponding to a molecular diameter D = 0.438nm

I would like to know if my reasoning is correct; especially the equation V = b/N
I'm also confused about the inclusion of the a constant in the problem when it isn't needed as far as I know.


 
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Hello Mike,

I think what you did looks good. You can check it here with the simplest of all googles.
There it also explains the other coefficient has to do with attractive force among molecules -- and indeed isn't relevant.
 
Hi there, sorry for the late reply. Thank you for confirming my solution; I was starting to wonder if there was another shortcut that involves a...
 

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