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1. The problem statement, all variables and given/known data

An extreme sportsman jumps from one cliff to another of width (w) by leaping horizontally by vo. With a height difference of h (where the starting cliff is higher) what is vo so he doesn't miss the cliff? (also, what is the direction of motion)

2. Relevant equations

xo=0

x=w, y=0

vox=0

ax=0

voy=0

ay=-g

yo=h

3. The attempt at a solution

Determine time of landing:

0=y=h-(1/2)gt[tex]^{2}[/tex]

t=[tex]\sqrt{2h/g}[/tex]

Determine vo:

x=vot

vo=xo/t=x[tex]\sqrt{g/2h}[/tex]

vo=w[tex]\sqrt{9.81/2h}[/tex]

does this look correct so far?

I'm stuck at finding the direction of motion, i know the equation is:

[tex]\vartheta[/tex]=tan[tex]^{-1}[/tex]vy/vx

vy=-gt=[tex]\sqrt{2hg}[/tex]

=tan[tex]^{-1}[/tex][tex]\sqrt{2hg}[/tex]/(w[tex]\sqrt{g/2h}[/tex])

=tan[tex]^{-1}[/tex] (2h/w) degrees of the horizontal component

but, i'm not sure if this is exactly right...

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# Homework Help: Variable Problem for 2D Kinematics

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