Variable substitution question(diff)

  1. [tex]\frac{xy'}{(\ln x\arctan y)-1}=(1+y^2)\arctan y\\[/tex]
    [tex]t=\arctan y\\[/tex]
    [tex]\frac{x}{\ln (x)t-1}=\frac{t}{t'}\\[/tex]

    [tex]\frac{x}{\ln (x)t-1}=\frac{tdx}{dt}\\[/tex]
    [tex]xdt=(\ln (x)t-1)tdx\\[/tex]
    [tex]\frac{dt}{\ln (x)t-1}=\frac{dx}{x}\\[/tex]
    still cant beak it as one type of variable on each side
    so i substitute by another variable
    [tex]z=\ln x\\[/tex]
    i dont know how to separate each variable type on one side
    so i could integrate

  2. jcsd
  3. First of all, your last substitution should result in
    I'm not exactly sure on a good substitution to use, but since this is a Bernoulli ODE, you can use that method.
Know someone interested in this topic? Share this thead via email, Google+, Twitter, or Facebook

Have something to add?