Vector Basics: Finding V1 and V2 | Homework Statement and Equations

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Homework Help Overview

The discussion revolves around two vectors, V1 and V2, where V1 is stated to be parallel to the xz plane and V2 is perpendicular to V1 with a known magnitude of 10 units. Participants are exploring how to determine the direction and characteristics of V1 based on the given conditions.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the possibility of determining V1's direction but note that its magnitude cannot be established. Questions arise regarding how to find the direction of V1, particularly through the use of cross products with V2 and the normal vector to the xz plane.

Discussion Status

The discussion is active with various interpretations being explored. Some participants suggest that V1's direction can be derived from the cross product of V2 and the normal vector to the xz plane, while others question the feasibility of determining V1's direction given the lack of specific information about V2.

Contextual Notes

There is an ongoing examination of the implications when V2 and the normal vector are parallel, leading to discussions about the resulting cross product and its physical significance. Participants are also considering the constraints of the problem, particularly the limitations imposed by the known magnitude of V2.

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Homework Statement



I have two vectors V1 and V2.
V1 is parallel to xz plane
V2 is perpendicular to V1
V2 is 10 units.Can i get V1?

Homework Equations





The Attempt at a Solution



Force triangle?Can''t solve?
 
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You can only get V1's direction, not magnitude.
 
How can we get the direction of V1?
 
The normal to the xz plane is the vector V3=(0,1,0). If V1 is parallel to the xz plane then it is perpendicular to V3. So V1 is perpendicular to V2 and V3. So a direction for V1 is given by the vector cross product of V2xV3.
 
But from the given conditions, v2 (only the magnitude is known) is not given, how can you know v1's direction ?
 
The direction is the same as v2x(0,1,0). That's about all you can say. And if v2 is parallel to (0,1,0) then you can't say much of anything at all.
 
You said:
what will be the value of cross product V2 x V3?
 
My question:

what will be the value of cross product V2 x V3?
 
jrm2002 said:
My question:

what will be the value of cross product V2 x V3?

Ok, shorter answer. NO. You can't 'get' V1.
 
  • #10
But what will be the cross product V2 x V3, in an expression?
 
  • #11
If V2=(x,y,z), (x,y,z)x(0,1,0)=(-z,0,x) (look up cross product). The result is in the xz plane is perpendicular to V2.
 
  • #12
Plz help with another case:

1. If V2 and V3 are parallel
2. Hence V1 = the cross product of V2 x V3 evaluates to 0,0,0
3. What is the physical reason for this?
 
  • #13
The cross product is related to the area of the parallelogram created by the two vectors. What happens if they are parallel?
 
  • #14
Straight line?
 
  • #15
If you mean what I think you mean then yes. The area is zero. So the vector is zero.
 

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