Vector Diagram of Impulse: Is My Drawing Correct?

AI Thread Summary
The discussion centers on the correct representation of impulse in a vector diagram related to a collision between two objects, m1 and m2. Participants debate the appropriate interpretation of the change in momentum (Δp) and its representation as a vector, emphasizing that Δp experienced by m1 and m2 are equal and opposite. The consensus leans towards identifying the correct diagram as one that illustrates the relationship between the initial momentum of m1 and the impulse it experiences during the collision. Clarification is sought on which Δp to represent, with a focus on the object whose momenta are explicitly shown. The conversation highlights the complexities of visualizing momentum conservation in collision scenarios.
songoku
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Homework Statement
Object ##m_1## moves with velocity ##v_1## collides with object ##m_2## and has final velocity of ##v_{1}^{'}##. Which vector diagram is correct?
Relevant Equations
I = Δp
1650851226212.png


1650851276344.png


I think all the options are wrong. Since I = Δp = m1v1' - m1v1, I draw it like this:

1650851671241.png


Is my drawing wrong?

Thanks
 
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Your diagram is not different from one of the 5 choices (which one?) in the same manner that ##A - B## is not different from ##A + (-B).##
 
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At times, I think it is better to think of ##\Delta \vec p=\vec p_f - \vec p_i##
implicitly but "physically"
as what has to be added to ##\vec p_i## to get ##\vec p_f##: $$ \vec p_i + \Delta \vec p= \vec p_f$$
 
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Thank you very much kuruman and robphy
 
From conservation of momentum, I would be looking for the diagram in which the vector representing ##m_1v_1## is the vector sum of the other two.
 
songoku said:
Homework Statement:: Object ##m_1## moves with velocity ##v_1## collides with object ##m_2## and has final velocity of ##v_{1}^{'}##. Which vector diagram is correct?
Relevant Equations:: I = Δp
The question here is which ##\vec{\Delta p}## ? ##\vec{\Delta p}## experienced by ##m_2## or ##\vec{\Delta p}## experienced by ##m_1## ? Because they are equal and opposite.

Edited to show ##\vec{\Delta p}## as a vector.
 
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neilparker62 said:
The question here is which ##\Delta p## ? ##\Delta p## experienced by ##m_2## or ##\Delta p## experienced by ##m_1## ? Because they are equal and opposite.
I too considered this ambiguity. I decided that it is the Δp of the object whose initial and final momenta are shown because the initial and final momenta of the target mass could be anything. I classified this as a vector subtraction problem.
 
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Then the correct option is the one showing ##\vec{p_1} + \vec{\Delta p} = \vec{p_1}'## with ##\vec{\Delta p}## being the collision impulse experienced by mass ##m_1##. In which case I stand corrected in respect of post #5 in which I assumed ##\vec{\Delta p}## is the collision impulse experienced by (also) assumed stationary object ##m_2##. Tricky!
 
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