Vector Equations for line passing through a point

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To find a vector equation for a line passing through the point (4,3) and parallel to the vector i - 2j, use the formula <x,y> = <a,b> + t<c,d>, where (a,b) is the point and <c,d> is the direction vector. In this case, the equation becomes <x,y> = <4,3> + t<1,-2>. The confusion about needing a second point is clarified, as only one point and a direction vector are necessary to define the line. The dot product mentioned is not required for this specific problem. Understanding the relationship between the point and the direction vector simplifies the process of forming the vector equation.
Peter G.
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Hi,

I am a bit confused... I don't understand what is happening, I can't picture it:

Find a vector equation for the line passing through the point 4,3 and parallel to the vector i - 2j.

If r = p +t (q-p)

I only have one point, how can I use the fact it is parallel to help me? Point Q must be as such that the dot product of q - p and i - 2j must equal the magnitude of q - p * the magnitude of i - 2j?

Any help is appreciated

Thanks,
Peter
 
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The vector equation of a line through (a,b) in the direction D = <c,d>is

<x,y> = <a,b> + t<c,d>

All you need is a point and a direction vector, which you have given.
 

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