MHB Vector in 3d with given by magnitude and angle

Click For Summary
To express the vector in component form, start by recognizing that it lies in the yz plane with a magnitude of 2 and an angle of 30 degrees with the positive y-axis. The x-component is zero, which simplifies the vector to the form <0, v1, v2>. Using trigonometric definitions, v1 can be calculated as 2 * cos(30°) and v2 as 2 * sin(30°). The final vector in component form is <0, √3, 1>. Understanding these calculations is essential for accurately representing vectors in three-dimensional space.
cbarker1
Gold Member
MHB
Messages
345
Reaction score
23
Dear everyone,Direction Write the vector in component form.

v lies in the yz planeplane, has magnitude 2, and makes an angle of 30 degrees with the positive y axis.

Work
I know that the x component is zero.
<0,v1,v2​>

Thanks
Cbarker1
 
Mathematics news on Phys.org
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 25 ·
Replies
25
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
4K