A plane traveling at a speed of 1300 km/h in a northernly direction at a height of 5 km above the the ground suddenly climbs at an angle of 45 degrees to to horizon. Maintaining the speed and angle it releases a projectile as it passes through 7 km in altitude. Find the magnitude of the projectile's horizontal and vertical velocity.
I know projectile motion equations will be used. Vy=Vo+Ayt and X=Xo+Vxo*t
The Attempt at a Solution
I figured out that if it is released after it hits 7km the planes displacement in the x direction would be 2 km from the origin of the axis (not sure if relevant or not). The total height of 7 km will also come into play when figuring the projectile motion down, but I'm not sure how to get started when considering the direction of the projectile leaving the plane. Any help or just a nudge in the right direction would be greatly appreciated. Thank you!