Vector Mechanics — Double Gear Rolling on a Rack

AI Thread Summary
The discussion centers on deriving the equation ##\frac{x_A}{2\pi r_1} = -\frac{\theta}{2\pi}## in the context of a double gear rolling on a rack. Participants emphasize the need to define the variable ##\theta##, which represents the angle of rotation in radians, and its relationship to the distance traveled by point A. The conversation explores how far point A moves for one revolution, half a revolution, and for any given angle ##\theta##, clarifying that the distance is proportional to the radius of the gear. There is a request for further clarification from the original poster, but no response has been received. Understanding these concepts is crucial for solving the problem regarding the gear's angular velocity and the velocities of other components.
Alexanddros81
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Homework Statement
The double gear shown rolls on the stationary lower rack; the velocity of its
center A is 1.2 m/s directed to the right. Determine (a) the angular velocity
of the gear, (b) the velocities of the upper rack R and of point D of the gear.
Relevant Equations
-
Hi!
My first question: How does he get the equation ##\frac {x_A} {2πr_1} = -\frac {θ} {2π}## ?
 

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You forgot to define ##\theta## (Solution forgot it too !)
Ask youriself: how far does ##A## go to the right for one revolution (##\theta = 2\pi##) ? For half a revoluton ? For a given ##\theta ## ?
 
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Alexanddros81 said:
Homework Statement:: The double gear shown rolls on the stationary lower rack; the velocity of its
center A is 1.2 m/s directed to the right. Determine (a) the angular velocity
of the gear, (b) the velocities of the upper rack R and of point D of the gear.
Relevant Equations:: -

Hi!
My first question: How does he get the equation ##\frac {x_A} {2πr_1} = -\frac {θ} {2π}## ?
What is the definition of a radian? How is it connected to this question?
 
Chestermiller said:
What is the definition of a radian? How is it connected to this question?

A radian is ratio between length of the arc and its radius:

$$\theta = \frac {x} {r}$$

For a complete circle, it became:

$$\theta = \frac {2 \pi r} {r} \\
\theta = 2 \pi ~ \text {rad}$$
 
bagasme said:
A radian is ratio between length of the arc and its radius:

$$\theta = \frac {x} {r}$$

For a complete circle, it became:

$$\theta = \frac {2 \pi r} {r} \\
\theta = 2 \pi ~ \text {rad}$$
I was asking the OP to help him/her understand where the equation in question had come from.
 
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But we got no reaction whatsoever from @Alexanddros81 -- not so nice !
 
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Hi!
I will provide my thinking soon for this question
 
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BvU said:
You forgot to define ##\theta## (Solution forgot it too !)
Ask youriself: how far does ##A## go to the right for one revolution (##\theta = 2\pi##) ? For half a revoluton ? For a given ##\theta ## ?

for one revolution ##A## goes to the right ##2\pi r_1##. For half a revolution ##\pi r_1##.
For a given ##\theta## goes to the right ##\theta r_1##?
 
Alexanddros81 said:
For a given ##\theta## goes to the right ##\theta r_1##
No. Theta is an angle. It does not go to the right. You mean: For a given ##\theta##, A goes to the right ##\theta r_1##. Correct.

Now think the lower rack out of the way. Le A be a fixed axis
Ask youriself: how far does B (rack R) go to the right wrt A for one revolution (##\theta=2\pi##) ? For half a revoluton ? For a given ##\theta## ?
 
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