How Does Current Affect Rowing Across a River?

  • Thread starter Thread starter Michael_Light
  • Start date Start date
  • Tags Tags
    Explanation Vector
Click For Summary
To cross a river by the shortest possible path, the boat must be steered at a 60º angle upstream to counteract the current, ensuring the path is perpendicular to the banks. This is because any other angle would create a longer hypotenuse compared to the direct perpendicular route. To cross in the shortest possible time, the boat should be pointed directly across the river at a 90º angle, allowing it to utilize its full speed across the river. However, this will result in being carried downstream by the current. The discussion emphasizes the importance of understanding vector components in relation to the boat's speed and the river's current.
Michael_Light
Messages
112
Reaction score
0

Homework Statement



A girl can row a boat at 3 m/s in still water. She wishes to cross a 165m wide river in which the current flows at 1.5 m/s. Find the direction in which the boat must be steered in order to cross the river:

a) by the shortest possible route

b) in the shortest possible time

Homework Equations


The Attempt at a Solution



The answer from my book says that for

a) In order to cross the river by the shortest possible path, the actual path must be at right angles to the banks, which is θ=cos-1 1.5/3 = 60º

b) in order to cross in shortest possible time, the boat must be steered at right angles to the bank, i.e θ=90º.

But i don't really understand. Can anyone elaborate more for me...?

Why in order to cross the river by the shortest possible path, the actual path must be at right angles to the banks?

and why in order to cross in shortest possible time, the boat must be steered at right angles to the bank?

Please guide me. :confused:
 
Physics news on Phys.org
First, geometrically, the shortest path across a river, represented by two parallel lines, is perpendicular to the banks. If you need more detail, any other straight line across the river would form the hypotenuse of a right triangle having the perpendicular route as a leg. And c^2= a^2+b^2 so the hypotenuse is always longer than either leg. And any curved path is longer than the straight line between the two endpoints.

But in order to actually go across the river perpendicular to the banks, you must "point" the boat upstream to overcome the downstream flow of the river. That is, the velocity vector of the boat must have two components, one upstream, equal to but opposite the speed of the river, in order to cancel it, and one across the river that actually contributes to the motion of the boat. The time it takes to cross the river, along this shortest path, is the width of the river divided by cross river component of the boat's speed.

If, instead, you point the boat straight across the river, while letting the river take the boat downstream, with the same boat speed as above, all of the boats "still water" speed will go to that cross river component rather than just the speed minus the component required to cancel the river's speed. Of course, this assumes that you put the same effort, rowing, sailing, engine, etc. into maintaining the same "forward" speed for the boat.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
7K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 33 ·
2
Replies
33
Views
4K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 8 ·
Replies
8
Views
10K