Vector problem with traveling car

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Homework Help Overview

The problem involves calculating the resultant displacement of a car that travels 215 km west and then 85 km southwest. The subject area pertains to vector addition and displacement in physics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to resolve the vectors into components but questions the assumption of a 45-degree angle for the southwest direction. Some participants clarify that southwest indeed implies a 45-degree angle.

Discussion Status

The discussion is ongoing, with some participants providing clarifications regarding the angle associated with the southwest direction. There is an exploration of how to approach vector resolution, but no consensus has been reached on the method to be used.

Contextual Notes

There is a lack of explicit numerical angles provided in the problem statement, leading to questions about assumptions in vector direction. The original poster expresses uncertainty about the use of 45 degrees without it being explicitly stated.

ThomasMagnus
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A car is driven 215 km west then 85km south west. Find the resultant displacement (magnitude and direction) from the Point of origin.

My solution would be to resolve the two vectors into components. How can I do this if there is no angle given?

In the solution to the problem, they are using 45 degrees as the angle. Where does the 45 come from? If you are not given an angle are you to assume the angle is 45 degrees?

Thanks!
 
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The angle is given, its just not in numerical form. The question states 85km south west, that south west indicates 45 degrees.

hope this helps

-Chris
 


For vectors, the total displacement is from the origin to the final location.

Try drawing this problem out.

For example, you drive 5km east, and 5 km south. Our human logic states that we drove 10 km. however, this isn't the displacement. We've only displaced ourselves by the hypotenuse of the 2 directions. In this case our 10 km 'drive' displaced us: the root of 5^2 + 5^2 (Pythagoras theory: A^2 + B^2 = C^2) = 7.07km.

To summarize, we drove for 10km, but were only displaced by 7.07km.

Hope this helps.
 


Great thanks!
 

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